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emmainna [20.7K]
2 years ago
9

You are volunteering to help with the soccer team fundraiser for Valentine's Day. Your team promised to deliver one 16 ounce bag

of nuts to students with at least 60% chocolate-covered nuts inside.
When you arrive, instead of a bag of plain nuts and chocolate nuts, you find there are two bags of mixed nuts. The first says it is 50/50 plain and chocolate covered. The second bag contains 80% chocolate covered nuts.

The team is dismayed, but you come up with a solution. You suggest combining

ounces* of the 50/50 bag of nuts with

ounces* of the 80% bag of nuts, to make it an approximately 60% mixture.

*estimate

Then another student on the team says, "Wait, we promised at least 60%. So if we just do half and half won't we be giving them at least 60%?" This student

correct.
Mathematics
1 answer:
icang [17]2 years ago
7 0

The student, who suggests that if we do half and half of each bag, we will be giving them at least 60%,<u> is correct</u>.

<h3>What is the implication of the phrase "at least"?</h3>

The phrase "at least" means the minimum that is true or possible.

Mathematically, by "at least," we mean 'equal to or greater than.'

<h3>Data and Calculations:</h3>

Since each bag of nuts contain 16 ounces,

The 1st bag contains x/2 ounces (50%) of plain nuts and x/2 ounces (50%) of chocolate-covered nuts.

The 2nd bag contains x/5 ounces (20%)of plain nuts and 4x/5 ounces (80%) of chocolate-covered nuts.

If half of the 1st bag is mixed with half of the 2nd bag, each bag will contain only 65% (that is, 25% (50%/2) from the 1st bag and 40% (80%/2) from the 2nd bag).

Thus, the student, who suggests that if we do half and half of each bag, we will be giving them at least 60%, <u>is correct</u> since they will not be given less than 60% of chocolate-covered nuts inside.

Learn more about proportions at brainly.com/question/870035

#SPJ1

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