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3 years ago

A function is given by the equation h (x)=x 2 squared +6x-3. what is h (3)?

1 answer:

5 0

Your "h (x)=x 2 squared +6x-3" is ambiguous. If you meant "x squared," then you need only write x^2 OR "x squared," but NOT "x 2 squared."

I will assume that by "h (x)=x 2 squared +6x-3" you actually meant:

h(x)=x^2 +6x-3. To find h(3), subst. 3 for x: h(3) = (3)^2 + 6(3) - 3, or

h(3) = 9 + 18 - 3, or h(3) = 24.

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Rod is saving Php2000 in a bank at the end of each month which gives an interest of 1% compounded monthly.How much is the saving

agasfer [191]

Answer:

Php2040.38

Step-by-step explanation:

Given

$P = 2000$ --- Principal

$r = 1\%$ --- Rate

$t = 2\ years$ --- Time

$n = 12$ --- monthly

Required

Determine the amount at the end of two years

This is calculated as:

$A = P(1 + \frac{r}{n})^{nt}$

So, we have:

$A = 2000(1 + \frac{1\%}{12})^{12*2}$

$A = 2000(1 + \frac{1}{100*12})^{24}$

$A = 2000(1 + \frac{1}{1200})^{24}$

$A = 2000(\frac{1200+1}{1200})^{24}$

$A = 2000(\frac{1201}{1200})^{24}$

$A = 2000*1.02019$

$A = 2040.38$

Hence, the final amount is: Php2040.38

7 0

2 years ago

How do you solve this? My algebra 2 teacher taught it to us in class but it still confuses me! Thank you!

nataly862011 [7]

$\bf \cfrac{\frac{1}{8}-\frac{1}{2x}}{\frac{1}{12x}-\frac{1}{3x^2}} \begin{array}{llll} \leftarrow \textit{our LCD here will just be }8x\\[0.9em] \leftarrow \textit{our LCD down here will be }12x^2 \end{array}$

$\bf \cfrac{~~\frac{(x)1-(4)1}{8x}~~}{\frac{(x)1-(4)1}{12x^2}}\implies \cfrac{~~\frac{x-4}{8x}~~}{\frac{x-4}{12x^2}}\implies \cfrac{~~\begin{matrix} x-4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{\underset{2}{~~\begin{matrix} 8x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{\stackrel{3x}{~~\begin{matrix} 12x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{~~\begin{matrix} x-4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\implies \cfrac{3x}{2}$

8 0

3 years ago

What is the average rate of change from x = −3 to x = −4?

Vika [28.1K]

Answer:

-2

Step-by-step explanation:

Since it would be immensely helpful to know the equation of this parabola, we need to figure it out before we can continue. We have the work form of a positive upwards-opening parabola as

$y=a(x-h)^2+k$

where a is the leading coefficient that determines the steepness of lack thereof of the parabola, x and y are coordinates of a point on the graph, and h and k are the coordinates of the vertex. We know the vertex: V(-3, -3), and it looks like the graph goes through the point P(-2, -1). Now we will fill in the work form equation and solve for a:

$-1=a(-2-(-3))^2-3$

which simplifies a bit to

$-1=a(1)^2-3$

and

-1 = a(1) - 3. Therefore, a = 2 and our parabola is

$y=2(x+3)^2-3$

Now that know the equation, we can find the value of y when x = -3 (which is already given in the vertex) and the value of y when x = -4. Do this by subbing in the values of x one at a time to find y. When x = -3, y = -3 so the coordinate of that point (aka the vertex) is (-3, -3). When x = -4, y = -1 so the coordinate of that point is (-4, -1). The average rate of change between those 2 points is also the slope of the line between those 2 points, so we will use the slope formula to find it:

$m=\frac{-1-(-3)}{-4-(-3)} =\frac{2}{-1}=-2$

And there you have it! I'm very surprised that this question sat unanswered for so very long! I'm sorry I didn't see it earlier!

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2 years ago

Helpp plss?????plsss

zmey [24]

Answer:2/3 x 15 = 10

1/4 x 5 = 1.25

2 1/2 x 1/7 = 5/14

Step-by-step explanation:

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3 years ago

Meet-gni-wbcb-dyr

spayn [35]

Step-by-step explanation:

hold up let me work it out and i will answer with full explanation

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2 years ago