Answer: the values of each prize are
$330,$300,$270,$240,$210,$180,$150.
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Given: </h3>
- sum of total prize money=$1680
- number of students=7
- each prize is $30 less than the preceding prize
The above conditions are in the form of an Arithmetic Progression(AP)
with sum of series() 1680 , 7 terms(n) in the AP and common ratio(d)=30
Let the first term of the AP be 'a'.
The 7th award is $150
The 6th award is $(150+30)=$180
The 5th award is $(180+30)=$210
The 4th award is $(210+30)=$240
The 3rd award is $(240+30)=$270
The 2nd award is $(270+30)=$300
The 1st award is $(300+30)=$330
Reference: To know more about Arithmetic Progressions :
brainly.com/question/13989292
//SPJ2