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Ymorist [56]
1 year ago
7

Please help!

Mathematics
1 answer:
AfilCa [17]1 year ago
8 0

Answer:

a.) P(HH|C)=2/5

Explanation:

Given following:

  • P(HH) = 7
  • P(C) = 10
  • P(HH ∩ C) = 4
  • P(HH ∪ C) = 13

Solving steps:

\sf P(HH|C) = \dfrac{P(HH \cap C) }{P(C)}

\sf P(HH|C) = \dfrac{4 }{10}

\sf P(HH|C) = \dfrac{2 }{5}

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Sarah is doing research on the average age of first-year resident physicians. She wants her estimate to be accurate to within 1
WINSTONCH [101]

Answer: The number of first-year residents she must survey to be 95% confident= 263

Step-by-step explanation:

When population standard deviation (\sigma)  is known and margin of error(E) is given, then the minimum sample size (n) is given by :-

n=(\dfrac{z^*\sigma}{E})^2, z* = Two-tailed critical value for the given confidence interval.

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So, n= (\dfrac{1.96\times8.265}{1})^2 =(16.1994)^2\\\\= 262.42056036\approx263\ \ \ [\text{Rounded to the next integer}]

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3 years ago
Between which two integers does 35 lie?
iren2701 [21]

The answer is the first choice, "5 and 6."

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3 years ago
A sociologist wants to determine if the life expectancy of people in africa is less than the life expectancy of people in asia.
Colt1911 [192]

Answer:

The sample statistics are attached.

First, we need to determine the hypothesis.

The null hypothesis should be: H_{o} : u_{africa} \geq u_{asia}.

The alternative hypothesis should be: H_{a}: u_{africa}

The next step is about calculating the<em> t statistics </em>based on the samples. This <em>t test </em>will give the probability value or p-value, which determines if there's enough to reject the null hypothesis. The formula we need to use to find the t-value is: t=\frac{x_{1}-x_{2}  }{\sqrt{\frac{s_{1} ^{2} }{n_{1} } +\frac{s_{2} ^{2} }{n_{2} } } }

Replacing all the values into the formula, we have:

t=\frac{52.4-58.1}{\sqrt{\frac{(7.4)^{2} }{45}+\frac{(8.8)^{2} }{35}  } } \\t=\frac{-5.7}{\sqrt{1.2+2.2} } =\frac{-5.7}{1.8} =-3.2

Therefore, the t-value is -3.2.

Now, we using a level of significance of 0.01, and a degree of freedom (df) of 34, we use the t-table to find the p-value for this results. (df = N -1; in this case, we take the smaller sample, which is 35, giving us 34 of df).

Therefore, according to the table attached, <em>the p-value is less than 0.01,</em> which is less than our level of significance. This result means that the null hypothesis is rejected. In other words, there's enough evidence to say that <em>the life expectancy of people in Africa is less than the life of expectancy of people in Asia.</em>

<em></em>

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