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3 years ago

5

Why are one fourth and three eights represented with negative numbers on the number line in the example

1 answer:

Nikitich [7]3 years ago

8 0

Answer:

i cant say since there arent any number lines shown

Step-by-step explanation:

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Change 4 5/7 and 7 into improper fractions

Elden [556K]

ANSWER:

4 5/7= 83/7

7= 7/1

4 0

3 years ago

Cos (-Ø)= √3/3 sinØ <0 what is the value of sinØ?

Inga [223]

Answer:

sin∅= - √6/3

Step-by-step explanation:

Trigonometric function cos is even function which mean:

cos (-∅) = cos ∅

Trigonometric function sin is odd function which mean:

sin (-∅) = - sin∅ => sin∅ < 0

The basic trigonometric equation reads in this case with angle marked ∅:

sin²∅ + cos²∅ = 1 => sin²∅ = 1 - cos²∅ => sin²∅ = 1 - ( √3/3 )² =>

sin²∅ = 1 - (3/9) => sin²∅ = 1 - (1/3) = (3/3) - (1/3) = 2/3 => sin∅ = - √(2/3) =>

sin∅ = - √2/√3 => sin∅ = - √6/3

God with you!!!

3 0

4 years ago

The line integral of xydx×x^2y^3dy where c is the triangle with points (0,0) (1,0) (1,2) using green's theorem

lyudmila [28]

If $\mathcal C$ is the boundary of the triangle $D$ , then by Green's theorem

$\displaystyle\int_{\mathcal C}xy\,\mathrm dx+x^2y^3\,\mathrm dy=\iint_D\left(\frac{\partial(x^2y^3)}{\partial x}-\frac{\partial(xy)}{\partial y}\right)\,\mathrm dA$
$=\displaystyle\int_{x=0}^{x=1}\int_{y=0}^{y=2x}(2xy^3-x)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x\int_{y=0}^{y=2x}(2y^3-1)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x(8x^4-2x)\,\mathrm dx=\frac23$

4 0

3 years ago

Monique made several batches of soup for a potluck supper. Each batch required 3/4 of a pound of potatoes, and she used a total

Rina8888 [55]

Answer:

B and E

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Homework due at 12:00<br> I Need Help

Leya [2.2K]

Answer:

<em>k = - 7.5 </em>

Step-by-step explanation:

Slope "m" of a line through points

( $x_{1}$ , $y_{1}$ )

( $x_{2}$ , $y_{2}$ )

is m = $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

Slopes of perpendicular lines are opposite reciprocal: $m_{1}$ $m_{2}$ = - 1

~~~~~~~~~~~~~~~

The slope of a line through points (0, 7) and (2, 10)

$m_{1}$ = $\frac{10-7}{2-0}$ = $\frac{3}{2}$

Slope of perpendicular line through points (3, 5) and (k, 12) is $m_{2}$ = $-\frac{2}{3}$

or $m_{2}$ = $\frac{12-5}{k-3}$

$\frac{7}{k-3}$ = $-\frac{2}{3}$

2(k - 3) = - 21

k - 3 = - 10.5

<em>k = - 7.5</em>

6 0

3 years ago