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forsale [732]
2 years ago
7

The __________ is the process of posing and answering research questions using controlled techniques that include systematic, or

derly observation and the collection of data.
Mathematics
1 answer:
Katarina [22]2 years ago
8 0

Answer:

Scientific Method:

Step-by-step explanation:

Scientific method is the set of basic rules that must be followed for the production of knowledge that has the rigor of science, that is, it is a method used for research and verification of a certain content. For several authors, the scientific method is the logic applied to science.

i hope this

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What is the standard form of this function?
Solnce55 [7]

Answer:

D. Rx) = x2 - 4x + 10

Step-by-step explanation:

R(x)=(x-2)^2+6

R(x)=(x-2)^2+6

=(x-2)(x-2)+6

=x^2-2x-2x+4+6

=x^2-4x+10

R(x) = x^2 - 4x + 10

Option D is the answer

8 0
3 years ago
In a class, 7 students walk to school, two fifths ride and 32% are dropped off by their parents.
Svet_ta [14]
10 students ride the bus.
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3 years ago
When people make estimates, they are influenced by anchors to their estimates. A study was conducted in which students were aske
12345 [234]

Answer:

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2> 0

where μ1: mean calorie estimation for the cheesecake group and μ2: mean calorie estimation for the organic salad group.

There is enough evidence to support the claim that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first (P-value=0.0000002).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Suppose that the study was based on a sample of 20 people who thought about the cheesecake first and 20 people who thought about the organic fruit salad first, and the standard deviation of the number of calories in the cheeseburger was 128 for the people who thought about the cheesecake first and 140 for the people who thought about the organic fruit salad first.</em>

<em>At the 0.01 level of significance, is there evidence that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first?"</em>

<em />

This is a hypothesis test for the difference between populations means.

The claim is that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2> 0

The significance level is 0.01.

The sample 1 (cheese cake), of size n1=20 has a mean of 780 and a standard deviation of 128.

The sample 2 (organic salad), of size n2=20 has a mean of 1041 and a standard deviation of 140.

The difference between sample means is Md=-261.

M_d=M_1-M_2=780-1041=-261

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{128^2}{20}+\dfrac{140^2}{20}}\\\\\\s_{M_d}=\sqrt{819.2+980}=\sqrt{1799.2}=42.417

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-261-0}{42.417}=\dfrac{-261}{42.417}=-6.153

The degrees of freedom for this test are:

df=n_1+n_2-1=20+20-2=38

This test is a left-tailed test, with 38 degrees of freedom and t=-6.153, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.0000002) is smaller than the significance level (0.01), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first.

3 0
3 years ago
A human resources representative claims that the proportion of employees earning more than $50,000 is less than 40%. To test thi
bearhunter [10]

Answer:

The statistic for this case would be:

z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}

And replacing we got:

z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92

Step-by-step explanation:

For this case we have the following info:

n =700 represent the sample size

X= 305 represent the number of employees that earn more than 50000

\hat p=\frac{305}{700}= 0.436

We want to test the following hypothesis:

Nul hyp. p \leq 0.4

Alternative hyp : p>0.4

The statistic for this case would be:

z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}

And replacing we got:

z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92

And the p value would be given by:

p_v = P(z>1.922)= 0.0274

4 0
3 years ago
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