Answer:

Step-by-step explanation:
we know that
To find out the difference In the fuel tank of the two cars, subtract the fuel tank capacity of the compact car from the fuel tank capacity of the luxury sedan
so

Answer:The number of days it will take to sell the same amount of cookies is 3 and the number of tubs that will be sold is 27
Step-by-step explanation:
Let x represent the number of days it will take either of them to sell the same number of tubs.
Let y represent the total number of tubs that that Joseph will sell in x days.
Let z represent the total number of tubs that that Dwayne will sell in x days.
Joseph has already sold 3 tubs. If Joseph starts selling 8 tubs per day, it means that in x days, the number of tubs that he will sell will be
y = 8x + 3
Dwayne hasn't sold any yet. If Dwayne begins selling 9 tubs per day, it means that in x days, the number of tubs that he will sell will be
z = 9x
To determine the number of days it will take to sell the same amount of cookies, we will equate y to z. It becomes
8x + 3 = 9x
9x - 8x = 3
x = 3
The number of tubs that each will sell will be 9x = 9×3 = 27
Answer: y=2x+1 is parallel & y=-2x+5 is perpendicular
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
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<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.