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satela [25.4K]
2 years ago
6

Hi I need help with this question 2 1/7+3/7(3x-5)=-4

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
5 0

An equation is formed of two equal expressions. The value of x is -28/9.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The given expression can be simplified as,

2 \frac17+\dfrac37(3x-5)=-4\\\\\dfrac{15}{7} + \dfrac{9x-15}{7} = -4\\\\ \dfrac{15+9x-15}{7} = -4\\\\9x = -28\\\\x = \dfrac{-28}{9}

Hence, the value of x is -28/9.

Learn more about Equation:

brainly.com/question/2263981

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3 years ago
What is 1258 rounded to the nearest hundred?
Murljashka [212]

Answer:

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Step-by-step explanation:

The number in the place to the right of the hundreds place is 5, in the tens place. That digit is greater than 4, so the rounding is to the next higher hundred: 1300.

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Question 8 -
FinnZ [79.3K]

Answer:

Her wage on the 8th day is $105 ⇒ answer d

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- The average of set of data = The sum of data/the number of data

- The sum of data = the average of set of data × the number of data

∵ Cindy worked for 15 consecutive days

∵ She is earning an average wage of $91 per day

∴ Her total earning = 91 × 15 = $1365

∵ Her average earning during the first 7 days is $87 per day

∴ Her total earning in the first 7 days = 87 × 7 = $609

∵ Her average earning during the last 7 days is $93 per day

∴ Her total earning in the last 7 days = 93 × 7 = $651

- Her total earning in the 14 days is the sum of the earning in the

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∵ Her total earning in the 14 days = 609 + 651 = $1260

∵ Her total earning in the 15 days is $1365

- To find her wage on the 8th day subtract her wage of the 14 days

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7 0
2 years ago
If 1200 cm^2 of material is available to make a box with a square base and an open top find the largest possible volume of the b
strojnjashka [21]
Surface area of box=1200 cm² 
<span>Volume of box=s²h </span>
<span>s = side of square base </span>
<span>h = height of box </span>
<span>S.A. = s² + 4sh </span>
<span>S.A. = surface area or 1200 cm², s²
 = the square base, and 4sh = the four 'walls' of the box. </span>
<span>1200 = s² + 4sh </span>
<span>1200 - s² = 4sh </span>
<span>(1200 - s²)/(4s) = h </span>


<span>v(s) = s²((1200 - s²)/(4s)) </span>
<span>v(s) = s(1200 - s²)/4 . </span>
<span>v(s) = 300s - (1/4)s^3</span>

by derivating
<span>v'(s) = 300 - (3/4)s² </span>
<span>0 = 300 - (3/4)s² </span>
<span>-300 = (-3/4)s² </span>
<span>400 = s² </span>
<span>s = -20 and 20. </span>
again derivating
<span>v"(s) = -(3/2)s </span>
<span>v"(-20) = -(3/2)(-20) </span>
<span>v"(-20) = 30 </span>
<span>v"(20) = -(3/2)(20) </span>
<span>v"(20) = -30 </span>


<span>v(s) = 300s - (1/4)s^3 </span>
<span>v(s) = 300(20) - (1/4)(20)^3 </span>
<span>v(s) = 6000 - (1/4)(8000) </span>
<span>v = 6000 - 2000 
v=4000</span>
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