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Andre45 [30]
1 year ago
6

a teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the te

st
Mathematics
1 answer:
natka813 [3]1 year ago
6 0

The question is incomplete. The complete question is

A teacher promised a movie day to the class that did better, on average, on their test. The box plot shown in the below-mentioned figure shows the results of the test.

Which class should get the reward, and why?

- The 2nd-period class should get the reward. They have the highest score, a perfect 100.

- The 2nd-period class should get the reward. They have a higher median.

- The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

- The 4th-period class should get the reward. Their lowest score is an outlier and should be thrown out.

The box plot shown in the question provides the information that
In 2nd period the minimum of the data is 77, first quartile is 78, median of the data is 89, third quartile is 92 and the maximum of the data is 100.
Hence, the mean of the results of 2nd period is

\frac{77+78+89+92+100}{5}=87.2

In 2nd period the minimum of the data is 72, first quartile is 83, median of the data is 89, third quartile is 96 and the maximum of the data is 98.

Hence, the mean of the results of the 4th period is

\frac{72+83+89+96+98}{5}=87.6

Hence, obviously, the 4th period is having more mean.

Moreover, we can observe that if more of the marks are on the higher side the average will automatically be more. Hence, as the first and the third quartiles are more on the 4th-period, so the average marks for the 4th period must be better.

So, just by observing the box plot, we can give the statement that  "The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class. "

Therefore, the 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

Learn more about box plots here-

brainly.com/question/1523909

#SPJ10

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6x + 9y = -15
tester [92]
Answer:
A
Step-by-step explanation
You can divide 6x,9y and -15 by 3
6x/3=2x
9y/3=3y
-15/3=(-5)
Combine them to get the factored form of 6x+9y-15:
3(2x+3y-5)
4 0
2 years ago
Rosario and Enrqiue are in the same mathematics
Paul [167]

Answer:Enrqiue's average was higher than Rosario's average by 3

Step-by-step explanation:

Rosario's average= sum of 78, 77, 64, 86, and 70/ no of scores= 375/5= 75

Enrique's average=sum of 90, 61, 79, 73, and 87/ no of scores = 390/5=78

78-75=3

3 0
3 years ago
Pi/6 is the reference angle for:
Ksju [112]
Option B. 13π/6 and Option D. 5π/6

To get the reference angle π/6 for the given angles we will check each angle given in the options.
A. 8π/6
Since 8π/6 means 240° which lies in 3rd quadrant. Therefore reference angle of 240°= 240-180 = 60° or π/3
B. 13π/6
13π/6 means 390° which lies in first quadrant.
Therefore reference angle = 390-360 = 30° or π/6
C. 3π/6
Since 3π/6 means 90° therefore reference angle of 90° is the same as 90°.
Or the reference angle is = π/2
D. 5π/6
5π/6 means angle is 150° which lies in second quadrant therefore reference angle of 150° = 180-150 = 30° or π/6
answer is Option B and D.
8 0
2 years ago
What’s 1:6 equal too in two ways
IceJOKER [234]

Hey!

------------------------------------------------

Solution:

We can get two different ways of 1:6 by add +1:+6.

1 + 1 = 6 + 6

2:12

2 + 1 = 12 + 6

3:18

------------------------------------------------

Answer:

2:12 and 3:18

------------------------------------------------

Hope This Helped! Good Luck!

7 0
3 years ago
Determine which of these relations are transitive. The variables x, y, x', y represent integers A.x~y if and only if x +y is pos
Veronika [31]

Answer:

A, B, C,D, F

Step-by-step explanation:

The explanation for why each option is transitive and option E is not transitive is explained in the attachment

6 0
3 years ago
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