A fruit stand sells 6 oranges for $3 and 3 grape fruit for $2.40 .Lionel buys 10 oranges and 11 grapefruits. how much does Lione
l spend on the fruit?
2 answers:
6oragnes=3dollars
divide 6
1oragne=0.5dollar
3grapefruit=2.4dollar
divide3
1grapefruit=0.6dollar
10 oranges and 11 grapefuites
(10 times 0.5)+(11 times 0.6) =
5+6.6=11.6
answer is $11.6
Lionel bought 10 oranges and 11 grapefruits.
6 oranges cost $3.
1 orange would cost $3/6
10 oranges would then cost $3/6 * 10 = $5.
3 grapes cost $2.40.
1 grape would cost $2.4/3
11 grapes would then cost $2.4/3 * 11 = $8.8.
Total amount spent = $5 + $8.8 = $13.8
You might be interested in
Answer:
-2v = (-2x3, -2x4) = (-6,-8)
A^2-3a+14 is the answer :)
Answer:5
Step-by-step explanation:
Answer:
The answer is already 82.8
Step-by-step explanation:
The .8 is already to the tenth so it is 82.8
Answer:
C) f(n) = 5n-1
Step-by-step explanation: