The intensity of a fire alarm that measures 125 dB loud is 268,337.29
<h3>Formula and expressions</h3>
Given the expression L=10 logI
where;
- L is the loudness
- I is the intensity of the sound.
Given the following parameters
L = 125dB
Substitute the given parameters into the following
L=10 logI
125 = 10logI
logI = 125/10
logI = 12.5
I = e^12.5
I = 268,337.29
Hence the intensity of a fire alarm that measures 125 dB loud is 268,337.29
Learn more on subject of formula here: brainly.com/question/657646
Answer:
a. The probability is not equal to 1
b. P (A') = 0.70
c. P ( A U B ) = 0.80
d. P ( A' ∩ B' ) = 0.20
Step-by-step explanation:
a. Because these A and B are disjoint
b. since the probability of A is 0.30 then the probability of A compliment is
P(A compliment ) = 1 - P (A)
P(A compliment ) = 1-0.30
P(A compliment ) = 0.70
c. Since event are disjoint then intersection of A and B is 0, so probability of A U B is;
P ( A U B ) = P (A) + P(B) - P(A∩ B)
P ( A U B ) = 0.30 + 0.50 - 0
P ( A U B ) = 0.80
d. The inetrsection of compilments of A and B are:
by using De Morgan's Law we have,
P ( A' ∩ B' ) = P [(A U B )']
P ( A' ∩ B' ) = 1 - P ( A U B )
P ( A' ∩ B' ) = 1 - 0.80
P ( A' ∩ B' ) = 0.20
The third answer would be correct. TUWV ~ DEFG; 6:4.5
This is because 6 is dilated to 4.5.
Hope this helped!
No because 2/5 is the same as 2 divided by 7, so 2/5 = 0.4 where 5 divide by 7 is 0.714….. so they’re not equal.