Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Answer:
If solving for x then x = -3/2 +y/2
If solving for y then y = -3-2x
Step-by-step explanation:
For x: Divide both sides by 2
For y: Subtract 2x from both sides of the equation
Sol_
( 3 - 2 ) + ( 4 - 1 ) ^ 2
= 1 + 3^2
= 1 + 9
= 10
Answer is " - " .
hope it helped !
Thanks!
Answer:
Step-by-step explanation:
To find the distance, we can use the distance formula:
when the given points are 
and 
Plug in the points (-6.25,5) and (-3.75,2)
Therefore, the distance between the two coordinates is , or approximately 3.91.
I hope this helps!
