Question

Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. Round your answer to four decimal places.
P ( X > 2 ) , n = 5 , p = 0.7

Answer 1

The value of the probability P(x > 2) is 0.8369

How to evaluate the probability?

The given parameters are:

n = 5

p =0.7

The probability is calculated as:

$P(x) = ^nC_x *p^x * (1 - p)^x$

Using the complement rule, we have:

P(x > 2) = 1 - P(0) - P(1) - P(2)

Where:

$P(0) = ^5C_0 *0.7^0 * (1 - 0.7)^5$

P(0) = 1 *1 * (1 - 0.7)^5 = 0.00243

$P(1) = ^5C_1 *0.7^1 * (1 - 0.7)^4$

P(1) = 5 *0.7^1 * (1 - 0.7)^4 = 0.02835

$P(2) = ^5C_2 *0.7^2 * (1 - 0.7)^3$

P(2) = 10 *0.7^2 * (1 - 0.7)^3 = 0.1323

Recall that:

P(x > 2) = 1 - P(0) - P(1) - P(2)

So, we have:

P(x > 2) = 1 - 0.00243 - 0.02835 - 0.1323

Evaluate

P(x > 2) = 0.83692

Approximate

P(x > 2) = 0.8369

Hence, the value of the probability P(x > 2) is 0.8369

Read more about probability at:

brainly.com/question/25870256

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