Yes, the porch is 12 feet wide.
If 1 inch = 2 feet, and if she makes the porch 6 inches wide, then you multiply the 6inches by 2, since 1 inch is equal to 2 feet.
Answer:
4
Step-by-step explanation:
In triangle ΔPQR, we have;
The incenter of the triangle = The point <em>T</em> = The point of the intersection of the angle bisectors
Therefore, the perpendicular distances from <em>T</em> to the sides of ΔPQR are the radius, <em>r</em>, of the inscribed circle of ΔPQR
∴ WT = UT = ST = r
From the figure, WT = 4
∴ WT = UT = ST = 4
ST = 4
The Answer Is: 10 * 10 * 10 = 10 * 3
Perimeter of a rectangle = 6x + 8
Solution:
Given area of a rectangle = ![2x^2+7x+3](https://tex.z-dn.net/?f=2x%5E2%2B7x%2B3)
Let us first factor the given polynomial.
![2x^2+7x+3=2x^2+x+6x+3](https://tex.z-dn.net/?f=2x%5E2%2B7x%2B3%3D2x%5E2%2Bx%2B6x%2B3)
![=(2x^2+x)+(6x+3)](https://tex.z-dn.net/?f=%3D%282x%5E2%2Bx%29%2B%286x%2B3%29)
Taking out common terms in the above expression
Taking out common term
in the above expression
![=(2x+1)(x+3)](https://tex.z-dn.net/?f=%3D%282x%2B1%29%28x%2B3%29)
![2x^2+7x+3=(2x+1)(x+3)](https://tex.z-dn.net/?f=2x%5E2%2B7x%2B3%3D%282x%2B1%29%28x%2B3%29)
Area of a rectangle = l × b
Therefore,
and ![b=x+3](https://tex.z-dn.net/?f=b%3Dx%2B3)
Perimeter of a rectangle = 2(l + b)
![=2[(2x+1)+(x+3)]](https://tex.z-dn.net/?f=%3D2%5B%282x%2B1%29%2B%28x%2B3%29%5D)
![=2(2x+1+x+3)](https://tex.z-dn.net/?f=%3D2%282x%2B1%2Bx%2B3%29)
![=2(3x+4)](https://tex.z-dn.net/?f=%3D2%283x%2B4%29)
![=6x+8](https://tex.z-dn.net/?f=%3D6x%2B8)
The answer is same if you take <em>l</em> = x + 3 and <em>b</em> = 2x + 1.
Hence, perimeter of a rectangle = 6x + 8.