Question

(Algebra2 HELP please)

Answer 1

Maximizing profit, is a way of getting the highest possible profit, from a function.

The bakery should make 45 loaves of A and 0 loaves of B, to maximize profit

To do this, we make use of the following representations.

x represents source A, and y represents source B

So, we have:

Constraint 1:

A uses 5 pounds, and B uses 2 pounds of oats.

Available: 180

The above condition is represented as;

$\mathbf{5x + 2y \le 180}$

Constraint 2:

A and B use 3 pounds of flour each.

Available: 135

The above condition is represented as;

$\mathbf{3x + 3y \le 135}$

Objective function

A yields $40, while B yields $30

So, the objective function is:

$\mathbf{Maximize\ Z = 40x + 30y}$

So, we have:

$\mathbf{Maximize\ Z = 40x + 30y}$

Subject to

$\mathbf{5x + 2y \le 180}$

$\mathbf{3x + 3y \le 135}$

$\mathbf{x,y \ge 0}$

See attachment for the graph of the subjects

From the graph, we have the corner points to be:

$\mathbf{(x,y) = \{(0,45),(30,15),(45,0)\}}$

Substitute these values in the objective function

$\mathbf{Z = 40(0) +30(45) = 1350}$

$\mathbf{Z = 40(30) +30(15) = 1650}$

$\mathbf{Z = 40(45) +30(0) = 1800}$

The maximum value of Z is at: (45,0)

This means that: the bakery should make 45 loaves of A and 0 loaves of B, to maximize profit

Read more about maximizing functions at:

brainly.com/question/14728529