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qaws [65]
1 year ago
8

NEED HELP ON THIS ASAP!!!!!!

Mathematics
1 answer:
Keith_Richards [23]1 year ago
8 0

Answer: Choice B (If you need to do questions like this in the future i recommend using the desmos graphing calculator online, inputting the equations and comparing them)

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The value of a collector’s item is expected to increase exponentially each year. The item is purchased for $500. After 2 years,
Andreyy89
Y = 500(1 + r)^x; where r is the rate and x is the number of years.
500(1 + r)^2 = 551.25
(1 + r)^2 = 551.25/500 = 1.1025
1 + r = sqrt(1.1025) = 1.05

Therefore, the equation that represents y, the value of the item after x years is
y = 500(1.05)^x
7 0
3 years ago
What is the area of the regular hexagon? This is due tomorrow please help! :)
tester [92]

Check the picture below.

so then, the perimeter of that hexagon will  just be the sum of all its 6 sides, or namely 3⅖ + 3⅖ + 3⅖ + 3⅖ + 3⅖ + 3⅖, or just 6( 3⅖ ).

\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=3\\ p=6\left(3\frac{2}{5} \right) \end{cases}\implies A=\cfrac{1}{2}(3)\left[ 6\left(3\frac{2}{5} \right) \right]\implies A=\cfrac{1}{2}(3)\left[ 6\left(\cfrac{17}{5} \right) \right] \\\\\\ A=\cfrac{1}{2}(3)\left(\cfrac{102}{5} \right)\implies A=\cfrac{1}{2}\left( \cfrac{306}{5} \right)\implies A=\cfrac{153}{5}\implies A=30\frac{3}{5}

3 0
3 years ago
Item
mamaluj [8]
What's your question?
7 0
2 years ago
Please help!<br><br> Answers:<br> 15<br> 70<br> 55<br> 105
yulyashka [42]
Equation:
3x + 10 = (180 - (5x - 5) ) \div 2 \\ ... \\ x = 15 \\
3x+10 = 45+10 = 55
The answer is 55 because this is a isosceles triangle.
7 0
3 years ago
A catalog company that receives the majority of its orders by telephone conducted a study to determine how long customers were w
lana66690 [7]

Answer: 0.3679

Step-by-step explanation:

The cumulative distribution function for exponential distribution is :-

P(x)=1-e^{-\lambda x}, where \lambda  is the mean of the distribution.

Given :  A mean length of waiting time equal 2.8 minutes

i.e. Mean number of calls answered in a minute \lambda=\dfrac{1}{2.8}

Now, the proportion of callers is put on hold longer than 2.8 minutes is given by :_

P(x>2.8)=1-P(x

Hence, the proportion of callers is put on hold longer than 2.8 minutes = 0.3679

8 0
3 years ago
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