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3 years ago

Help me with this problem

Mathematics

2 answers:

Paha777 [63]3 years ago

8 0

The answer to your question is C because they are related ints

siniylev [52]3 years ago

5 0

The answer of your problem is C. Because 25 and 100 are related integers.

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Which pair of expressions is equivalent? ОА. A. 4x – 12 and 3(x – 3) B. 2(x + 3) + 1 and 2x + 6 C. 11x – 4 + 2x and 13x – 4 D. X

Blababa [14]

Answer:

$11x - 4 + 2x$ and $13x - 4$

Step-by-step explanation:

Given

Options A to D

Required

Determine the equivalent pair

To do this, we solve each options one after the other.

$(a):\$

$4x - 12$ and $3(x - 3)$

Open bracket

$4x - 12$ and $3 * x - 3 * 3$

$4x - 12$ and $3x - 9$

The above pairs are not equivalent

$(b):\$

$2(x + 3) + 1$ and $2x + 6$

Open bracket

$2x + 2*3 + 1$ and $2x + 6$

$2x + 6 + 1$ and $2x + 6$

$2x + 7$ and $2x + 6$

The above pairs are not equivalent

$(c):$

$11x - 4 + 2x$ and $13x - 4$

Collect Like Terms

$11x + 2x - 4$ and $13 - x$

$13x - 4$ and $13 - x$

The above pairs are equivalent

5 0

2 years ago

Assume that the probability of a defective computer component is 0.02. Components arerandomly selected. Find the probability tha

solmaris [256]

Answer:

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

Step-by-step explanation:

Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.

First six not defective, each with 0.98 probability.

7th defective, with 0.02 probability. So

$p = (0.98)^6*0.02 = 0.0177$

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

Find the expected number and variance of the number of components tested before a defective component is found.

Inverse binomial distribution, with $p = 0.02$

Expected number before 1 defective(n = 1). So

$E = \frac{n}{p} = \frac{1}{0.02} = 50$

Variance is:

$V = \frac{np}{(1-p)^2} = \frac{0.02}{(1-0.02)^2} = 0.0208$

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=5%20%2B%204%20-%20%28%205%20-%20%286%20-%205%29%29" id="TexFormula1" title="5 + 4 - ( 5 - (6 -

Ket [755]

(6-5)=1 (5-1)=4 5+4=9 9-4=5

8 0

2 years ago

Read 2 more answers

If f x equals x -3 + g x equals 1 - x 2 - 9 find ( f og) (x and give any restrictions on its domain

evablogger [386]

$\begin{gathered} f(x)=x-3 \\ g(x)=\frac{1}{x^2-9} \\ (\text{fog)(x)}=\frac{1}{x^2-9}-3 \end{gathered}$

the denominator cannot be zero, because the division by zero is not defined, therefore:

$\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}$

Therefore the domain of (f o g)(x) is:

$D\colon(-\infty,-3)\cup(-3,3)\cup(3,\infty)$

3 0

10 months ago

I just this one please someone help

Step2247 [10]

Answer:

100

Step-by-step explanation:

because 4, 3, and 2 all make 180 and 4 and 2 are both 40 so you add that which makes 80 and then you take 180 and subtract 80 which gives you 100

6 0

2 years ago

Read 2 more answers