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2 years ago

A prism and two nets are shown below:

Mathematics

2 answers:

AURORKA [14]2 years ago

7 0

Part B because it’s correct

Novosadov [1.4K]2 years ago

7 0

B is correct, give brainliest pls

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5. Write a real-world problem that can be represented by the<br> expression 21 + (12 x 2).

Setler [38]

Step-by-step explanation:

Anna Bought 3 Toys each worth 7$. after the purchase, it is announced that the price of the toys has risen to 12$, and Anna decides to Buy 2 More toys before the price rises again. in total, how much did Anna Spend?

5 0

2 years ago

Brockman Corporation's earnings per share were $3.50 last year, and its growth rate during the prior 5 years was 7.0% per year.

fredd [130]

Answer:

The number of years it would take is $n = 2 \ years$

Step-by-step explanation:

From the question we are told that

The earning per share is $P =$ $3.50

The growth rate is r = 7.0%

The duration is $t = 5 \ years$

Generally the future value is mathematically represented as

$A = P(1 + \frac{r}{100} )^n$

Where P is the present value

n is the time period

A is the future value which is mathematically evaluated as

$A = 3 * P$

substituting value

$A = 3 * 3.50$

$A =$ $ 10.5 0

$A = P(1 + \frac{r}{100} )^n$

$10.5 = 3.5(1 + \frac{7}{100} )^n$

$10.5 = 3.225^n$

Taking log of both sides

$log 10.5 = nlog 3.225$

$1.0212 = n(0.5085)$

$n = \frac{1.0212}{(0.5085)}$

$n = 2 \ years$

4 0

3 years ago

Write the other side of this equation so that the equation is true for NO values of u

Lunna [17]

Answer: 6(u-2)+2= 6u+13

7 0

2 years ago

Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

5 0

2 years ago

Y-3=2(x+1)<br> Can you guys please help me solve for y

Tatiana [17]

Answer:

First, you have to rewrite the question in a way to isolate your Y. This means moving the -3 over to the other side.

Y = 2(x+1) + 3

Now, you should multiply the 2 out in the parenthesis.

Y=2x+2+3

Now, combine like terms! In this case, your like terms are 2 and 3.

Y=2x + 5

Because there are no more like terms, and Y is completely isolated, Y=2x + 5 is your answer!

6 0

3 years ago