Answer:
For given linear equation having infinite many solution the value of k is 20 .
Step-by-step explanation:
Given as :
The equation is 2 (4 x + 10) = 8 x + k
For infinite many solution , if the variable cancel out to zero then it will have infinite many solutions
<u>So, from given linear equation</u>
i.e 2 (4 x + 10) = 8 x + k
Or, 2 × 4 x + 2 × 10 = 8 x + k
Or, 8 x + 2 × 10 = 8 x + k
Or, 8 x + 20 = 8 x + k
Or, k + (8 x - 8 x) = 20
Or, k + 0 = 20
∴ k = 20
So, The vale of k = 20
Hence, For given linear equation having infinite many solution the value of k is 20 . Answer
Answer:
Question 1. (2.2, -1.4)
Question 2. (1.33, 1)
Step-by-step explanation:
Equations for the given lines are
-----(1)
It is given that this line passes through two points (0, 2.5) and (2.2, 1.4).
------(2)
This equation passes through (0, -3) and (2.2, -1.4).
Now we have to find a common point through which these lines pass or solution of these equations.
From equations (1) and (2),
x =
x = 2.2
From equation (2),
y = -1.4
Therefore, solution of these equations is (2.2, -1.4).
Question 2.
The given equations are y = 1.5x - 1 and y = 1
From these equations,
1 = 1.5x - 1
1.5x = 2
x =
Therefore, the solution of the system of linear equations is (1.33, 1).
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Answer:
(a) plane NOU
Step-by-step explanation:
The points identified on plane <em>L</em> are {M, N, O, U}. All but point U are on the same line.
To identify the plane we need to name 3 non-collinear points. U must be one of them. The other two could by any two from the set {M, N, O}.
One possible name for plane <em>L</em> is plane NOU.
