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mel-nik [20]
2 years ago
9

the ratio of cats and dogs at the city pound is 92 to 144.which statement descrbes this relationship?

Mathematics
2 answers:
Alexeev081 [22]2 years ago
5 0

Answer:

There are 23 cats for every 36 dogs at the city pound

Step-by-step explanation:

This means that for every group of 92 cats at the city compound there is a group of 144 dogs. So it also means that for every group of 23 cats there is a group of 36 dogs.

92 to 144 or 92/144 = 23/26  or 23 to 36

<h2>Hope This Helps Out</h2>
Zolol [24]2 years ago
4 0

Answer:

8:12

around every 8(7.6)cats there will be 12 dogs

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slamgirl [31]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2927231

————————

You can actually use either the product rule or the chain rule for this one. Observe:

•  Method I:

y = cos² x

y = cos x · cos x


Differentiate it by applying the product rule:

\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x\cdot cos\,x)}\\\\\\&#10;\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x)\cdot cos\,x+cos\,x\cdot \dfrac{d}{dx}(cos\,x)}


The derivative of  cos x  is  – sin x. So you have

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\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark

—————

•  Method II:

You can also treat  y  as a composite function:

\left\{\!&#10;\begin{array}{l}&#10;\mathsf{y=u^2}\\\\&#10;\mathsf{u=cos\,x}&#10;\end{array}&#10;\right.


and then, differentiate  y  by applying the chain rule:

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For that first derivative with respect to  u, just use the power rule, then you have

\mathsf{\dfrac{dy}{dx}=2u^{2-1}\cdot \dfrac{d}{dx}(cos\,x)}\\\\\\&#10;\mathsf{\dfrac{dy}{dx}=2u\cdot (-sin\,x)\qquad\quad (but~~u=cos\,x)}\\\\\\&#10;\mathsf{\dfrac{dy}{dx}=2\,cos\,x\cdot (-sin\,x)}


and then you get the same answer:

\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>derivative chain rule product rule composite function trigonometric trig squared cosine cos differential integral calculus</em>

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