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2 years ago

Please help me :((((((

Mathematics

1 answer:

dsp732 years ago

7 0

Answer:

Answer D

Step-by-step explanation:

It says to divide f(x)/g(x), which is displayed in D and if we find the domain it would be x is not equal to -1/4

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7/8m^3 +3-1/2m^3. can u please help me solve this

user100 [1]

Answer:

3m^3/8 + 3

Step-by-step explanation:

It can't be solved but that's the most simplified version.

3 0

3 years ago

Read 2 more answers

Which expressions are equivalent

PolarNik [594]

Answer:

Options (B) and (C)

Step-by-step explanation:

The given expression is $(d^{\frac{1}{8}})^5$

By simplifying this expression,

$(d^{\frac{1}{8}})^5$

= $(\sqrt[8]{d})^{5}$

Option (B)

Similarly,

$(d^{\frac{1}{8}})^5$

= $d^{\frac{5}{8}}$

= $(d^{5})^{\frac{1}{8}}$

Option (C)

Therefore, Options (B) and (C) will be the correct options.

5 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Bogdan [553]

The radical expressions and their corresponding expression in rational exponent form are

$972^\frac 15 = 3\sqrt[5]{4}$ , $448^\frac 13 = 4\sqrt[3]{7}$ , $3528^\frac 12 = 42 \sqrt 2$ and $4050^\frac 14 = 3\sqrt[4]{50}$

<h3>How to match the tiles?</h3>

We start by evaluating each expression as follows:

$972^\frac 15$

Expand 972

$972^\frac 15 = (243 * 3)^\frac 15$

Take the 5th root of 243

$972^\frac 15 = 3* (4)^\frac 15$

Rewrite as:

$972^\frac 15 = 3\sqrt[5]{4}$

Next, we have:

$448^\frac 13$

Expand 448

$448^\frac 13 = (64 * 7)^\frac 13$

Take the 3rd root of 64

$448^\frac 13 = 4 * (7)^\frac 13$

Rewrite as:

$448^\frac 13 = 4\sqrt[3]{7}$

Next, we have:

$3528^\frac 12$

Expand 3528

$3528^\frac 12 = (1764 * 2)^\frac 12$

Take the square root of 1764

$3528^\frac 12 = 42 * (2)^\frac 12$

Rewrite as:

$3528^\frac 12 = 42 \sqrt 2$

Lastly, we have:

$4050^\frac 14$

Expand 4050

$4050^\frac 14 = (81 * 50)^\frac 14$

Take the 4th root of 81

$4050^\frac 14 = 3 (50)^\frac 14$

Rewrite as:

$4050^\frac 14 = 3\sqrt[4]{50}$

Read more about radical expressions at:

brainly.com/question/8952483

#SPJ1

5 0

2 years ago

How do find the domain and range of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7Bx-8%7D%7D" id="TexFormula1" tit

Kisachek [45]

$\sqrt{x-8}$ is undefined if the argument $x-8$ is negative, so you first need to require that

$x-8\ge0\implies x\ge8$

We're not done yet, though, because $\dfrac1{\sqrt{x-8}}$ still doesn't exist when $x=8$ , so we remove this from the domain and we're left with $x>8$ , or in interval notation, $(8,\infty)$

To find the range, consider the limits of the function as you approach either endpoint of the domain.

$\displaystyle\lim_{x\to8^+}\frac1{\sqrt{x-8}}=+\infty$
$\displaystyle\lim_{x\to\infty}\frac1{\sqrt{x-8}}=0$

Since $\dfrac1{\sqrt{x-8}}$ is positive everywhere, the range is $(0,\infty)$

3 0

3 years ago

Anybody help? I did the math but didn't do something correct...

djverab [1.8K]

Which question u need help with

5 0

3 years ago