Question

Simplify the monomials

Answer 1

Answer:

$(4a)^{-3}*^{-4}$

$x^m*x^n=x^{m+n}$

$(4a)^{-3}*a^{-4}$

$(-4)^{-3}\: a^{-3}*a^{-4}$

$4^{-3}\:a^{-3-4}$

$\cfrac{1}{4^3} \:a^{-7}$

$\boxed{\frac{1}{64a^{7}} }$

~

$(3xy)^2*(-4x^3y^2)^3$

$9x^2y^2*(64x^9y^6)$

$\boxed{-576x^{11}y^8}$

~

$(4a^{-1}b^5c^{-3})^3$

$(4)^3(a^{-1})^3(b^5)^3(c^{-3})^3$

$(4*4*4)\:a^{-1*3}\:b^{5*3}\:c^{-3*3}$

$64\:a^{-3}b^{15}c^{-9}$

$\boxed{\frac{64b^{15}}{a^3c^9}}$