Answer:
The magnitude of the electric force between these two objects
will be: 181.274 N.
i.e. F
N
Step-by-step explanation:
As
Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.
so
q₁ = 4.5 μC = 4.5 × 10⁻⁶ C
q₂ = 2.8 μC = 2.8 × 10⁻⁶ C
separated distance = d = 2.5 cm
Calculating the magnitude of the force between two charged objects using the formula:


∵ 
∵ 


∵ 
∵ 

F
N
Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.
i.e. F
N
Answer:
1.58 meters
Step-by-step explanation:
Answer:
don't know
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
-
(x + 3) > x - 3 ( multiply both sides by 2 to clear the fraction )
- (x + 3) > 2x - 6 ← distribute parenthesis on left side by - 1
- x - 3 > 2x - 6 ( subtract 2x from both sides )
- 3x - 3 > - 6 ( add 3 to both sides )
- 3x > - 3
divide both sides by - 3, reversing the symbol as a result of dividing by a negative quantity
x < 1
Answer:
175/25
Step-by-step explanation:
i think this answers you question