Answer:
Hi I am willing to help you. What is your question?
Step-by-step explanation:
To solve for E you'll add 867 to 108.
E - 867 = 108
E = 108 + 867
E = 975
Hope this helps :)
Answer:
Third choice from the top is the one you want
Step-by-step explanation:
This whole concept relies on the fact that if the index of a radical exactly matches the power under the radical, both the radical and the power cancel each other out. For example:
and another example:
![\sqrt[12]{2^{12}}=2](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B2%5E%7B12%7D%7D%3D2)
Let's take this step by step. First we will rewrite both the numerator and the denominator in rational exponential equivalencies:
![\frac{\sqrt[4]{6} }{\sqrt[3]{2} }=\frac{6^{\frac{1}{4} }}{2^{\frac{1}{3} }}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7B6%7D%20%7D%7B%5Csqrt%5B3%5D%7B2%7D%20%7D%3D%5Cfrac%7B6%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%7D%7B2%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%7D)
In order to do anything with this, we need to make the index (ie. the denominators of each of those rational exponents) the same number. The LCM of 3 and 4 is 12. So we rewrite as

Now we will put it back into radical form so we can rationalize the denominator:
![\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B12%5D%7B6%5E3%7D%20%7D%7B%5Csqrt%5B12%5D%7B2%5E4%7D%20%7D)
In order to rationalize the denominator, we need the power on the 2 to be a 12. Right now it's a 4, so we are "missing" 8. The rule for multiplying like bases is that you add the exponents. Therefore,

We will rationalize by multiplying in a unit multiplier equal to 1 in the form of
![\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B12%5D%7B2%5E8%7D%20%7D%7B%5Csqrt%5B12%5D%7B2%5E8%7D%20%7D)
That looks like this:
![\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }*\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B12%5D%7B6%5E3%7D%20%7D%7B%5Csqrt%5B12%5D%7B2%5E4%7D%20%7D%2A%5Cfrac%7B%5Csqrt%5B12%5D%7B2%5E8%7D%20%7D%7B%5Csqrt%5B12%5D%7B2%5E8%7D%20%7D)
This simplifies down to
![\frac{\sqrt[12]{216*256} }{\sqrt[12]{2^{12}} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B12%5D%7B216%2A256%7D%20%7D%7B%5Csqrt%5B12%5D%7B2%5E%7B12%7D%7D%20%7D)
Since the index and the power on the 2 are both 12, they cancel each other out leaving us with just a 2! Doing the multiplication of those 2 numbers in the numerator gives us, as a final answer:
![\frac{\sqrt[12]{55296} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B12%5D%7B55296%7D%20%7D%7B2%7D)
Phew!!!
Answer:
Write an equation that models the relationship between these variables. ... On Patricia's dairy farm, her cows produce an average of 3.8 gallons of milk per ... Define variables for the number of gallons of milk produced and the ... of milk produced. AND let in represent the number of minutes spent milking.
Step-by-step explanation: now you try
C. Feverishly he went through the remaining strips of paper