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fiasKO [112]
1 year ago
11

A Venn diagram is shown below: What are the elements of (A n B) ‘ ?

Mathematics
1 answer:
vesna_86 [32]1 year ago
8 0

The elements of (A n B)' are ( 3, 4 , 5 ,6). Option A

<h3>How to determine the set</h3>

The elements of this set (A n B) explains the common elements  of both sets without repetition

Set A = 3, 4

Set B = 5, 6

A n B = 1, 2

(A n B)' = Is the elements both A and B in common but is not found in the universal set

(A n B)'  = ( 3, 4 , 5 ,6)

Thus, the elements of (A n B)' are ( 3, 4 , 5 ,6). Option A

Learn more about Venn diagrams here:

brainly.com/question/4910584

#SPJ1

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33% of what number is 1.45? Round to the nearest tenth.
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Take the unknown number as 'y'.

=》33% = 33/100

=》1.45 = 145/100

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33/100 × y = 145/100

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prove that sin theta cos theta = cot theta is not a trigonometric identity by producing a counterexample
Zolol [24]

Answer:

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Begin with the right hand side:

R.H.S = cot θ = \frac{cos \ \theta}{sin \ \theta}

L.H.S = sin θ cos θ

so, sin θ cos θ ≠ \frac{cos \ \theta}{sin \ \theta}

So, the equation is not a trigonometric identity.

=========================================================

<u>Anther solution:</u>

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Assume θ with a value and substitute with it.

Let θ = 45°

So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2

R.H.S = cot θ = cot 45 = 1

So, L.H.S ≠ R.H.S

So, sin θ cos θ = cot θ is not a trigonometric identity.

5 0
2 years ago
1. A sum of money is shared among Jessica, Amanda, and Beverly in the ration 8:9:3
astra-53 [7]

Answer:

$200

Step-by-step explanation:

Amanda       Beverly

     9         :       3

difference between Amanda and Beverly = 9 - 3 = 6 portions.

∴ value of 6 portions = $60

   value of 1 portion  =  $ 60 / 6

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Total sum of money to be shared = value of 1 portion x Total no. of portions

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8 0
2 years ago
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