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VARVARA [1.3K]
2 years ago
13

Evaluate the expression.

Mathematics
1 answer:
Zinaida [17]2 years ago
6 0

Answer:

-2(10(-4))²

-2(-40)²

-2 × 1600

= -3200

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A map of a rectangular park has a length of 4 inches and a width of 6 inches. It uses a scale of 1 inch for every 30 Miles. What
MakcuM [25]

Answer:

The actual area 21600 miles²

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- A drawing that shows a real object with accurate sizes reduced or

 enlarged by a certain amount called the scale

- Drawing scale is a ratio between the drawing length and the

 actual length

- To find the actual dimensions from the drawing dimensions use the

  scale drawing

*<em> Lets solve the problem</em>

- A map of a rectangular park has a length of 4 inches and a width

 of 6 inches

∴ The drawing dimensions are:

# length = 4 inches

# width = 6 inches

- The scale of the map is 1 inch foe every 30 miles

∴ The scale drawing is 1 : 30

- To find the actual area find the actual dimensions

∵ The scale drawing is 1 : 30

∵ The length = 4 inches and the width = 6 inches

- By using cross multiplication

∴  1        :        30

   4       :  actual length

   6       :  actual width

∴ Actual length = (4 × 30)/1 = 120

∴ Actual length = 120 miles

∴ Actual width = (6 × 30)/1 = 180

∴ Actual Width = 180 miles

∴ The actual dimensions are 120 miles and 180 miles

∵ The area of any rectangle = length × width

∴ The actual area = 120 × 180 = 21600

∴ The actual area 21600 miles²

5 0
3 years ago
What is the measure of the missing angle?​
goblinko [34]

Answer:

<u>The missing angle measures also 110°</u>

Step-by-step explanation:

Let's recall that If the transversal cuts across parallel lines (apparently, this particular case) then those alternate exterior angles have the same measure (.∠ 110° and ∠?) So in the figure given, the two alternate exterior angles measure the same.

<u>The missing angle measures also 110°</u>

4 0
3 years ago
Alejandro loves to go to the movies. He goes both at night and during the day. The cost of a matinee is 7 dollars. The cost of a
saw5 [17]

Answer:

<u>Alejandro went to 8 matinee shows and 4 evening shows.</u>

<u>Our system of equations:</u>

<u>x + y = 12</u>

<u>7x + 12y = 104</u>

Correct statement and question:

Alejandro loves to go to the movies. He goes both at night and during the day. The cost of a matinee is 7 dollars. The cost of an evening show is 12 dollars.

Alejandro went to see a total of 12 movies and spent $ 104. How many of each type of movie did he attend? Write a system of equations.

Source:

Previous question that can be found at brainly

Step-by-step explanation:

Step 1:

Let x to represent the number of matinee shows Alejandro went to.

Let y to represent the number of evening shows Alejandro went to.

Now, let's write our system of equations:

x + y = 12

7x + 12y = 104

*********************

x = 12 - y

*********************

7 (12 - y) + 12y = 104

84 - 7y + 12y = 104

5y = 104 - 84

5y = 20

y = 20/5

<u>y = 4 ⇒ x = 12 - 4 = 8</u>

<u>Alejandro went to 8 matinee shows and 4 evening shows.</u>

4 0
3 years ago
What is the median of the data?<br><br> 3<br> 8<br> 5<br> 5.5
ladessa [460]

Answer:

Median= middle number

(Example) 1, 4 ,6, 7 ,12

6 Would be the median here

so, 3, 3, 4, 4, 5, 5, 5, 5, 6, 7, 8,

5 Is the middle number and the median

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The mass of the Earth is 5.972x10^24 kg. the mass of the moon is 7.3 x 10^22kg. find the total mass, in kg, of the Earth and the
torisob [31]

Answer:

6045000000000000000000000 kg.

Step-by-step explanation:

We have been given that the mass of Earth is 5.972\times10^{24} kg. The mass of the Moon is 7.3\times10^{22} kg.

To find the total mass we will add mass of Earth and Moon.

First of all let us convert the given masses in standard form.

5.972\times10^{24}=5972000000000000000000000  

7.3\times10^{22}=73000000000000000000000

5.972\times10^{24}+7.3\times10^{22}  

5972000000000000000000000+73000000000000000000000

6045000000000000000000000

Therefore, the mass of Earth and Moon is 6045000000000000000000000 kg.

8 0
3 years ago
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