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expeople1 [14]
3 years ago
15

Please help it’s algebra 2

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0

The best way to tackle this is to put the answer that you know into a binomial factor. So the solution is x = 4. The binomial factor is (x - 4)


Now you can set up the other binomial factor. You have been given a huge hint. The third term is 28 and one of it's 2 factors is 7.  So this is what you know so far

(x - 4)(  x    7) But what is its sign? The 28 is positive. So the 7 must be minus giving you

(x - 4)(x - 7)  Are we done yet? No There's a 3 on the x^2. Does the 3 go with the x on (x - 4) or does the 3 go with the (x - 7)? We have been told that (x - 4) is one of the factors. No mention of a three. So we should try x - 7 first and write it like this.

(x - 4)(3x - 7)

I think if you remove the brackets, you will find that the middle term is - 19 (-12 - 7 = -19 ) which is exactly what it should be.


Answer (x - 4)(3x - 7)


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Hey I was just wondering if anyone can give me a better explanation on how to work with Negative numbers and and fractions when
Soloha48 [4]

Answer:

see explanation

Step-by-step explanation:

Given

\frac{6(2a-4c)-6(6a-4b)+3(4b-8c)}{4}

Distribute the 3 parenthesis on the numerator

= \frac{12a-24c-36a+24b+12b-24c}{4}

Collect like terms on the numerator

= \frac{-24a+36b-48c}{4}

Divide each of the terms on the numerator by 4

= \frac{-24a}{4} + \frac{36b}{4} + \frac{-48c}{4}

= - 6a + 9b - 12c ← factor out - 3 from each term

= - 3(2a - 3b + 4c)

Compare with

X(2a + Bb + Cc) to obtain

X = - 3, B = - 3, C = 4

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4 years ago
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natima [27]
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4 years ago
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gavmur [86]

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3 years ago
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4 years ago
How to solve <br> Y+2=4<br> Y-2=8
lakkis [162]

Answer:

First question -> y = 2

Second question -> y = 10

Step-by-step explanation:

<u>Step 1:  Solve y + 2 = 4</u>

Subtract 2 from both sides

y + 2 - 2 = 4 - 2

<em>y = 2</em>

<em />

<u>Step 2:  Solve y - 2 = 8</u>

Add 2 to both sides

y - 2 + 2 = 8 + 2

<em>y = 10</em>

<em />

Answer:  First question -> y = 2

               Second question -> y = 10

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4 years ago
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