Answer:

General Formulas and Concepts:
<u>Calculus</u>
The derivative of a constant is equal to 0
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Product Rule: ![\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29g%28x%29%5D%3Df%27%28x%29g%28x%29%20%2B%20g%27%28x%29f%28x%29)
Chain Rule: ![\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>

<u>Step 2: Rewrite</u>

<u>Step 3: Differentiate</u>
- Product Rule [Basic Power/Chain Rule]:

- Simplify:

- Rewrite:

- Add:

The inverse variation of y=3 would be y=1/3
The inverse variation of x=5 would be x=1/5
You just need to flip the variation around.
Your answer is: y=1/3; x=1/5
Have an amazing day and stay hopeful!
Answer:
The exponential function to model the duck population is:
f(n)=415*(1.32)^n, where:
x is the duck population
n is the number of years
Step-by-step explanation:
In order to calculate the duck population you can use the formula to calculate future value:
FV=PV*(1+r)^n
FV=future value
PV=present value
r=rate
n=number of periods of time
In this case, the present value is the initial population of 415 and the rate is 32%. You can replace these values on the formula and the exponential function to model the duck population would be:
f(n)=415*(1+0.32)^n
f(n)=415*(1.32)^n, where:
x is the duck population
n is the number of years
For a geometric sequence
<em>a</em>, <em>ar</em>, <em>ar</em> ², <em>ar</em> ³, …
the <em>n</em>-th term in the sequence is <em>ar</em> <em>ⁿ</em> ⁻ ¹.
The first sequence is
1, 3, 9, 27, …
so it's clear that <em>a</em> = 1 and <em>r</em> = 3, and so the <em>n</em>-th term is 3<em>ⁿ</em> ⁻ ¹.
The second sequence is
400, 200, 100, 50, …
so of course <em>a</em> = 400, and you can easily solve for <em>r</em> :
200 = 400<em>r</em> ==> <em>r</em> = 200/400 = 1/2
Then the <em>n</em>-th term is 400 (1/2)<em>ⁿ</em> ⁻ ¹.
Similarly, the other sequences are given by
3rd: … 4 × 2<em>ⁿ</em> ⁻ ¹
4th: … 400 (1/4)<em>ⁿ</em> ⁻ ¹
5th: … 5<em>ⁿ</em> ⁻ ¹
6th: … 1000 (1/2)<em>ⁿ</em> ⁻ ¹
7th: … 2 × 5<em>ⁿ</em> ⁻ ¹
V=10. You can solve this by using the rule of subtracting negative numbers, which means if you are subtracting a negative it is the same as adding a positive. So basically V + 9 = 19, making V equal 10.