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2 years ago

James read 4 pages in a book in 6 minutes how long would it take james to read 6 pages

Mathematics

2 answers:

OlgaM077 [116]2 years ago

6 0

Hi Mack17 the answer is 9 minutes

schepotkina [342]2 years ago

3 0

I think it would take him either 8 or 12 minutes

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I need help with my math, please help

storchak [24]

Answer:

x ≤6

Step-by-step explanation:

no more than means you can have 6 or less

x ≤6

4 0

2 years ago

Read 2 more answers

Four red, 8 blue, and 5 green balls are randomly arranged in a line. (a) What is the probability that the first 5 balls are blue

Over [174]

Answer:

it may be 3

Step-by-step explanation:

it may be bcz am not much good but still just trying

3 0

2 years ago

No scale is shown on this map of a wilderness area. The distance between Rose Lake and the main road is 3.5 mi. On the map it is

vivado [14]

Answer:

<em>The actual distance between Rose Lake and the hiking trail is 7 miles.</em>

Step-by-step explanation:

The actual distance between Rose Lake and the main road is 3.5 miles and the scaled distance on the map is 2 inch.

Suppose, the actual distance between Rose Lake and the hiking trail is $d$ miles.

Given that, the scaled distance from Rose Lake to the hiking trail on the map is 4 inch.

So, <u>according to the ratio of "scaled distance" to the "actual distance"</u>, the equation will be......

$\frac{2}{3.5}= \frac{4}{d} \\ \\ 2d=4*3.5=14\\ \\ d=\frac{14}{2}=7$

Thus, the actual distance between Rose Lake and the hiking trail is 7 miles.

4 0

2 years ago

Which of the following figures has 90 rotation symmetry?

garik1379 [7]

It would be a rectangle

6 0

2 years ago

he pulse rates of 179 randomly selected adult males vary from a low of 43 bpm to a high of 115 bpm. Find the minimum sample size

malfutka [58]

Answer:

Step-by-step explanation:

Given that:

Low = 43bpm

High = 115 bpm

Error = 3

α = 90%

To find the range estimate :

Standard destviation = (high - low) / 4

Standard deviation = (115 - 43) / 4

Standard deviation = 72/4 = 18

The sample size,(n) :

n = [(Zα/2 * sd)/E] ²

2 - tail = (Zα/2) = 1.645

[(Zα/2 * sd)/E] ² = [(1.645 * 18) / 3]² = (29.61/3)²

= 97.41

Sample size = 97

5 0

3 years ago