Begin by factoring 2 out of 2x^2 - 2x - 12 equals 0:
2(x^2 - x - 6) = 0
2(x - 3)(x + 2) = 0. 2 is never zero, but x-3 and x+2 can each be set = to 0:
This results in x = 3 and x = -2. The equation is true for these two x-values.
Remark
You have to read this carefully to know what way to write it.
One way you could write it would be
20 * x = 18 where x is the fraction. Now all you need do is divide.
Divide both sides by 20
20/20 * x = 18/20

But you should reduce this fraction. The way to do that is to factor 18 and 20 into primes.
18: 2 * 3 * 3
20: 2 * 2 *5
Cancel out the Highest common factor or 2.
You are left with
<<<< Answer
Answer:
around 3
Step-by-step explanation:
A solution to an equation is a number that can be plugged in for the variable to make a true number statement. Example 1: Substituting 2 for x in. 3x+5=11. gives.
Answer:
12
Step-by-step explanation: