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weeeeeb [17]
3 years ago
11

Write the number equal to 5 tens and 13 ones

Mathematics
1 answer:
cluponka [151]3 years ago
3 0
10 ones = 1 ten

6 tens 3 ones
63
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What is 22.3 rounded to the nearest hundred
WITCHER [35]

Answer:

100

Step-by-step explanation:

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What is m angle ABC​
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Answer:

3rd option: 60 degrees

Step-by-step explanation:

We can see in the diagram that the angle on C is a supplementary angle, which means that the sum of 135 and internal angle will be equal to 180 degrees.

Let x be the internal angle,

Then

x+135 = 180

x = 180-135

x = 45 degrees

So now we know that two interior angles of the triangle.

Also we know that sum of all internal angles of triangle is 180 degrees.

Using the same postulate:

A+B+C = 180

75 + B + 45 = 180

120+B = 180

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third option is the correct answer ..

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If....................
kobusy [5.1K]

Answer:

C  - 22

Step-by-step explanation:

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22 * -1  = -22

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Help me find the Angle <br><br><br> Angle FGB
Llana [10]

Answer:

∠FGB = 111°

Step-by-step explanation:

FGBE is a Kite. If you draw a line segment from F to B in bisects ∠GBE and ∠GFE into two triangles. The angles of a triangle with always add up to 180°. So, in triangle FBG, ∠GFB = 45° and ∠GBF = 24°. You subtract 45 and 24 from 180 and you are left with 111°.

5 0
3 years ago
Which real numbers are zeros of the function?
monitta
<h3><u>The roots are -1/2, 0, 2, and 3.</u></h3>

Let's trying factoring this polynomial.

We can factor an x out of each term to start.

x(2x^3 - 9x^2 + 7x + 6)

We now know one of the roots is going to be zero.

Using the rational roots theorem, and the remainder theorem, we can try to find some more roots that way.

Factors of 6: 1, 2, 3, 6.

Factors of 2: 1

Possible rational roots: +/-1/2, +/-1, +/-2, +/-3/2, +/-3, +/-6

Using the remainder theorem, we can plug these values into the polynomial, and if we get a remainder of zero, we know it's a root.

-1/2(2(-1/2)^3 - 9(-1/2)^2 + 7(-1/2) + 6) = 0

Our first root is -1/2.

We can successfully factor a -1/2 out of this polynomial.

After diving the polynomial by -1/2, we're left with: 2x^2 - 10x + 12.

We can now try using the AC method to get our last two roots.

First, we can factor this polynomial to simplify it.

Divide all terms by 2.

2(x^2 - 5x + 6)

Now let's try using the AC method.

The digits -3 and -2 satisfy the criteria.

2(x - 3)(x - 2)

We now have all of our roots: 0, -1/2, 2, and 3.


6 0
3 years ago
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