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1 year ago

Find the root of the function f(x)= 1/(1/3)

Mathematics

1 answer:

Dvinal [7]1 year ago

6 0

Answer:

Hello, look at the picture

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Grace earns $7 for each car she washes. She always saves$25 of her weekly earnings. This week she wants to have at least $65 in

lidiya [134]

Hi!
I think Grace needs to wash at least 6 cars. Please tell me if I'm wrong.

Thank you

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3 years ago

242 is the same as the total of b and 59<br><br> write in a equation

TiliK225 [7]

Answer:

Step-by-step explanation:

242=b+49

5 0

3 years ago

Read 2 more answers

Plsss answer, don’t need too show any work

Dovator [93]

Hey! The answer is 60 :)

8 0

2 years ago

Read 2 more answers

Marcus currently owns 200 songs in his iTunes collection. Every

UNO [17]

Answer:

Marcus will own 380 songs after a year.

Step-by-step explanation:

the equation would look like

$N=15m+200$

you

then put 12 in for (m)

n=15(12)+200

n=180+200

n=380

Marcus will own 380 songs after a year.

5 0

3 years ago

Ancient paintings were found on cave walls in South America. The Carbon-14 in the paintings was measured and was found to be 19%

balu736 [363]

Answer: C. 13,839 (the answer is not among the given options, however the result is near this value)

Step-by-step explanation:

The exponential decay model for Carbon- 14 is given by the followig formula:

$A=A_{o}e^{-0.0001211.t}$ (1)

Where:

$A$ is the final amount of Carbon- 14

$A_{o}=$ is the initial amount of Carbon- 14

$t$ is the time elapsed (the value we want to find)

On the other hand, we are told the current amount of Carbon-14 $A$ is $19\%=0.19$ , assuming the initial amount of Carbon-14 $A_{o}=$ is $100\%$ :

$A=0.19A_{o}$ (2)

This means: $\frac{A}{A_{o}}=0.19$ (2)

Now,finding $t$ from (1):

$\frac{A}{A_{o}}=e^{-0.0001211.t}$ (3)

Applying natural logarithm on both sides:

$ln(\frac{A}{A_{o}})=ln(e^{-0.0001211.t})$ (4)

$ln(0.19)=-0.0001211.t$ (5)

$t=\frac{ln(0.19)}{-0.0001211}$ (6)

Finally:

$t=13713.717years$ This is the age of the paintings and the option that is nearest to this value is C. 13839 years

6 0

2 years ago