All categories

2 years ago

How much gift paper is required to at least fully cover a

Mathematics

1 answer:

mestny [16]2 years ago

4 0

Answer:

Step-by-step explanation:

Discussion

Where does that 682 come from? It cannot be the surface area of a cube with a side of 50 inches.

The edge length is 50 inches, so s = 50

SA = 6 * 50^2

SA = 15000 in^2

Answer: So at the very minimum, you need 15000 square inches of wrapping paper.

You might be interested in

Help me please help help help help

Elena L [17]

Answer:

area of trapezium:

a+b divided by 2, times by the height.

so its 8+20=28.

28/2=14.

14*14=196.

area=196

Step-by-step explanation:

4 0

2 years ago

Emily is saving up to buy a new phone. She already has $75 and can save an

irga5000 [103]

Equation t= $7 times w

$7 times 4 = $28

5 0

3 years ago

Write the ordered pair that represents YZ. Then find the magnitude of YZ. y(-4,12), Z(1,19).

ki77a [65]

The magnitude of YZ is 8.6

Explanation:

Y( -4, 12)

Z ( 1, 19)

Magnitude of YZ = ?

We know:

$YZ = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

On substituting the value we get:

$YZ = \sqrt{(1+4)^2 + (19 - 12)^2} \\\\YZ = \sqrt{(5)^2 + (7)^2} \\\\YZ = \sqrt{25+49} \\\\YZ = \sqrt{74} \\\\YZ = 8.6$

Thus, the magnitude of YZ is 8.6

6 0

3 years ago

Read 2 more answers

2.1e-10 in standard form?

just olya [345]

2.1e-10
= 2.1 x 10^-10
= 0.00000000021

hope it helps

5 0

3 years ago

Read 2 more answers

Clearly mark on the coordinate plane the location of the ordered pairs and

ladessa [460]

Answer:

Point $J(4,0)$ lies on $x-$ axis and point $M(-2,-3)$ lies quadrant III.

Step-by-step explanation:

A coordinate plane is a plane that is divided into four quadrants by the coordinate axes.

Here, coordinate axes are $x-$ axis and $y-$ axis.

Let's first mark the points in the coordinate plane.

See the attached figure.

From the figure, it can be observed that point $J(4,0)$ lies on $x-$ axis and point $M(-2,-3)$ lies quadrant III.

3 0

3 years ago