1. The following diagram shows a slide at a park. a. Find the vertical distance from the ground to the top of the slide. b. Find

Question

2 years ago

6

the length of the slide. c. What is the area of the space under the slide. Steps 2 m /70* Slide 40° H

1 answer:

xenn [34] · Answer 1 · 2023-03-23T21:51:17+03:00

The area of the space under the slide is 2.10 square meters

<h3>The vertical distance</h3>

The diagram in the question is added as an attachment

The vertical distance is represented by h.

So, we have:

sin(70) = h/2

Solve for h

h = 2 * sin(70)

Evaluate

h = 1.88 m

Hence, the vertical distance is 1.88 m

<h3>The length of the slide</h3>

This is calculated using

sin(40) = h/Slide

This gives

sin(40) = 1.88/Slide

Solve for Slide

Slide = 1.88/sin(40)

Evaluate

Slide = 2.92

Hence, the length of the slide is 2.92 m

<h3>The area of the space under the slide</h3>

This is calculated using:

A = 0.5 * h * slide * sin(∅)

Where

∅ = 90 - 40 = 50

So, we have:

A = 0.5 * 1.88 * 2.92 * sin(50)

Evaluate

A = 2.10

Hence, the area of the space under the slide is 2.10 square meters