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Temka [501]
2 years ago
6

1. The following diagram shows a slide at a park. a. Find the vertical distance from the ground to the top of the slide. b. Find

the length of the slide. c. What is the area of the space under the slide. Steps 2 m /70* Slide 40° H​
Mathematics
1 answer:
xenn [34]2 years ago
4 0

The area of the space under the slide is 2.10 square meters

<h3>The vertical distance</h3>

The diagram in the question is added as an attachment

The vertical distance is represented by h.

So, we have:

sin(70) = h/2

Solve for h

h = 2 * sin(70)

Evaluate

h = 1.88 m

Hence, the vertical distance is 1.88 m

<h3>The length of the slide</h3>

This is calculated using

sin(40) = h/Slide

This gives

sin(40) = 1.88/Slide

Solve for Slide

Slide = 1.88/sin(40)

Evaluate

Slide = 2.92

Hence, the length of the slide is 2.92 m

<h3>The area of the space under the slide</h3>

This is calculated using:

A = 0.5 * h * slide * sin(∅)

Where

∅ = 90 - 40 = 50

So, we have:

A = 0.5 * 1.88 * 2.92 * sin(50)

Evaluate

A = 2.10

Hence, the area of the space under the slide is 2.10 square meters

Read more about triangles at:

brainly.com/question/11952845

#SPJ1

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