Question

1. The following diagram shows a slide at a park. a. Find the vertical distance from the ground to the top of the slide. b. Find the length of the slide. c. What is the area of the space under the slide. Steps 2 m /70* Slide 40° H​

Answer 1

The area of the space under the slide is 2.10 square meters

The vertical distance

The diagram in the question is added as an attachment

The vertical distance is represented by h.

So, we have:

sin(70) = h/2

Solve for h

h = 2 * sin(70)

Evaluate

h = 1.88 m

Hence, the vertical distance is 1.88 m

The length of the slide

This is calculated using

sin(40) = h/Slide

This gives

sin(40) = 1.88/Slide

Solve for Slide

Slide = 1.88/sin(40)

Evaluate

Slide = 2.92

Hence, the length of the slide is 2.92 m

The area of the space under the slide

This is calculated using:

A = 0.5 * h * slide * sin(∅)

Where

∅ = 90 - 40 = 50

So, we have:

A = 0.5 * 1.88 * 2.92 * sin(50)

Evaluate

A = 2.10

Hence, the area of the space under the slide is 2.10 square meters

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brainly.com/question/11952845

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