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VLD [36.1K]
3 years ago
10

Find X (Show Your Work) WILL MARK BRAINLIEST!

Mathematics
1 answer:
Rudiy273 years ago
6 0

Answer:

its 8 cause 2 times x is 40 40+-40= 0 so 2 times 4 is 8

Step-by-step explanation:

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Hellpppp me please !!!!!
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7 0
4 years ago
Round to the nearest hundredth 5/8
Solnce55 [7]
Eighths and their multiples are common fractions which I recommend memorizing, but to actually solve this, you use the literal meaning of a fraction and divide 5 by 8. See the long-division below (it was surprisingly difficult to type, so I hope it helps!).

To round 0.625 to the nearest hundredth, we go to the second decimal place, which is 5, so we round up to 0.63.

3 0
3 years ago
Find the slope of the line that connects the points (6, -2) and ( 10, 4)
Ivanshal [37]

Slope: 1.5

Work: I used the slope formula method which is y2 - y1/ x2 - x1. After plugging it in, the new equation is 4 - (-2) / 10 - 6. After subtraction, I had gotten 6/4. And when you divide 6/4, you get 1.5

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6 0
3 years ago
Read 2 more answers
Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=
jasenka [17]

Answer:

The function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

The function is continuous at point x=36 if:

  1. The function \\ f(x) exists at x=36.
  2. The limit on both sides of 36 exists.
  3. The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}

\\ f(36) = \frac{36*6}{900} = \frac{6}{25}

The limit of the \\ f(x) is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Since

\\ f(36) = \frac{6}{25}

And

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Then, the function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

8 0
3 years ago
It’s a multi step equation 2( a + 7 ) =9
max2010maxim [7]
Answer:
a = 2.5

Explanation:
2a + 14 = 9
a = 2.5
6 0
3 years ago
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