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2 years ago

Multiply Conjugates Using the Product of Conjugates Pattern

Mathematics

1 answer:

SpyIntel [72]2 years ago

5 0

Answer:

The product is the difference of squares is $\left(11-b\right)\left(11+b\right)=121-{{b}^2}$

Step-by-step explanation:

Explanation

The given expression is (11-b)(11+b).

We have to multiply the given expression.

Square the first term 11. Square the last term b.

$\begin{aligned}&(11-b)(11+b)=(11)^{2}-(b)^{2} \\&(11-b)(11+b)=121-b^{2}\end{aligned}$

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A delightful question.
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LekaFEV [45]

Answer: $y-1=\dfrac32(x+3)$

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = $\dfrac{d-b}{c-a}$

In graph(below) given line is passing through (-2,-4) and (2,2) .

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Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope = is given by

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Required equation: $y-1=\dfrac32(x+3)$

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3 years ago

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Step-by-step explanation:

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motikmotik

Answer:

can you show a link to the graph

Step-by-step explanation:

it will help me answer

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