Question

Multiply Conjugates Using the Product of Conjugates Pattern

Answer 1

Answer:

The product is the difference of squares is $\left(11-b\right)\left(11+b\right)=121-{{b}^2}$

Step-by-step explanation:

Explanation

• The given expression is (11-b)(11+b).

• We have to multiply the given expression.

• Square the first term 11. Square the last term b.

$\begin{aligned}&(11-b)(11+b)=(11)^{2}-(b)^{2} \\&(11-b)(11+b)=121-b^{2}\end{aligned}$