Answer: the rate at which the distance between the boats is increasing is 68 mph
Step-by-step explanation:
The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.
Let x represent the length the shorter leg(south) of the right angle triangle.
Let y represent the length the longer leg(east) of the right angle triangle.
Let z represent the hypotenuse.
Applying Pythagoras theorem
Hypotenuse² = opposite side² + adjacent side²
Therefore
z² = x² + y²
To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes
2zdz/dt = 2xdx/dt + 2ydy/dt- - - -- - -1
One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that
dx/dt = 32
dy/dt = 60
Distance = speed × time
Since t = 0.5 hour, then
x = 32 × 0.5 = 16 miles
y = 60 × 0.5 = 30 miles
z² = 16² + 30² = 256 + 900
z = √1156
z = 34 miles
Substituting these values into equation 1, it becomes
2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60
68dz/dt = 1024 + 3600
68dz/dt = 4624
dz/dt = 4624/68
dz/dt = 68 mph
We may draw a vertical that bisects the vertex angle and the shorter side of the triangle, to form a right-triangle with the measurements:
hypotenuse = 8
length = 1.5
We may then apply:
sin(∅) = P / H
sin(∅) = 1.5 / 8
∅ = 10.8 ≈ 11°
This is half of the vertex angle, so the vertex angle is:
11 * 2 = 22°
Answer:
84
Step-by-step explanation:
The interquartile range is obtained using the relation :
Third quartile (Q3). - First quartile (Q1)
From. The boxplot :
Q3 = 96
Q1 = 12
Interquartile range (IQR) = Q3 - Q1 = 96 - 12 = 84
Answer:
−33999/50
Step-by-step explanation:
2/100−680
=
1/50−680
=
−33999/50
