Pls help me with the answer , ty

Mathematics

1 answer:

katrin2010 [14]2 years ago

7 0

Using it's concept, the equivalent expression for the perimeter of the figure is:

2 + 3x2 + 4x2 + 5x2 + 8

<h3>What is the perimeter of a figure?</h3>

The perimeter of a figure is given by the total length of it's boundary.

Hence, for the figure given in this problem, the perimeter is:

2 + 3 + 3 + 4 + 4 + 5 + 8 + 5

2 + 3x2 + 4x2 + 5x2 + 8

More can be learned about the perimeter of a figure at brainly.com/question/26134384

#SPJ1

You might be interested in

Combien font 2 + 2 - 5

wel

Hello!

2 + 2 - 5 = -1.

I hope it helps!

3 0

3 years ago

A travel agent is booking trips for tourists who travel from New York to Chicago. Tourists have three choices for how to travel

Hitman42 [59]

List all the different combinations with total cost:

Airplane + van = 350 + 60 = $410

Airplane + cab = 350 + 40 = $390

Bus + van = 150 + 60 = $210

Bus + cab = 150 + 40 = $190

Train + van = 225 + 60 = $285

Train + cab = 225 + 40 = $265

There are 6 different combinations.

There are 2 that are more than $300

The probability would be quantity higher than 300 / total combinations.

Probability = 2/6 = 1/3

4 0

3 years ago

A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin

pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, $\text{ distance } =\text{ speed }\times \text{ time }$

$\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}$

We are given that, time taken for both are same. So $\frac{40}{a-11}=\frac{70}{a+11}$

$\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}$