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3 years ago

Write an equation for the description.

Mathematics

1 answer:

NeX [460]3 years ago

5 0

10 • x/2 + 4 = 7 is the equation

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2. Why are the triangles congruent?

Lady bird [3.3K]

Two triangles are congruent if their corresponding sides are equal in length, and their corresponding angles are equal in measure.

6 0

3 years ago

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I need help plz! It’s pre cal

Dmitry [639]

Please show a picture so that I can help you

3 0

3 years ago

The table below represents a linear function f(x) and the equation represents a function g(x):

Elza [17]

Answer:

(a) The slope of f(x) is greater than the slope of g(x)

(b) f(x) has a greater y intercept

Step-by-step explanation:

Given

$\begin{array}{cc}x & {f(x)} & -1&-9&0&-1&1&7 \ \end{array}$

$g(x) = 3x - 2$

Solving (a): Compare the slopes

The slope (m) of f(x) is calculated as;

$m = \frac{f(x_2) - f(x_1)}{x_2 - x_1}$

This gives:

$m = \frac{f(0) - f(1)}{0 - 1}$

$m = \frac{f(0) - f(1)}{- 1}$

Substitute values for f(0) and f(1)

$m = \frac{-1 - 7}{- 1}$

$m = \frac{-8}{- 1}$

$m = 8$

The slope of g(x) can be gotten using the following comparison

$g(x) = mx + b$

$m \to slope$

So:

$g(x) = 3x -2$

$m = 3$

$m_{f(x)} > m_{g(x)}$

Solving (b): Compare the y intercept

y intercept is when $x = 0$

From the table of f(x)

$f(0) = -1$

From the equation of g(x)

$g(x) = 3x -2$

$g(0) = 3*0-2$

$g(0) =-2$

$f(0) > g(0)$

6 0

3 years ago

Write the number 2,900 in scientific notation.

vitfil [10]

29^100
That’s the answer To the question

8 0

3 years ago

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Anyone know the answer to this algebra problem?

ikadub [295]

Answer: $\bold{a=1\qquad b=\dfrac{1}{16}\qquad c=\dfrac{1}{64}\qquad d=1\qquad e=\dfrac{4}{9}\qquad f=\dfrac{16}{81}}$

Step-by-step explanation:

$\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}$

$\begin{array}{c|l}\underline{\quad \bigg x \quad}&\underline{\quad \bigg(\dfrac{2}{3}\bigg)^x\qquad \qquad}\\\\-1&\bigg(\dfrac{2}{3}\bigg)^{-1}=\dfrac{3}{2}\\\\0&\bigg(\dfrac{2}{3}\bigg)^{0}=1\\\\2&\bigg(\dfrac{2}{3}\bigg)^{2}=\dfrac{2^2}{3^2}=\dfrac{4}{9}\\\\4&\bigg(\dfrac{2}{3}\bigg)^{4}=\dfrac{2^4}{3^4}=\dfrac{16}{81}\end{array}$

3 0

3 years ago