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Dima020 [189]
2 years ago
8

Need help with this diagram

Mathematics
1 answer:
Anit [1.1K]2 years ago
5 0

The width of the square garden is 4 feet

<h3>How to determine the width of the garden?</h3>

The area of the garden is given as:

x^2 + 20x + 75 = 171

Subtract 171 from both sides

x^2 + 20x - 96 = 0

Expand

x^2 + 24x - 4x - 96 = 0

Factorize

x(x + 24) - 4(x + 24) = 0

Factor out x + 24

(x - 4)(x + 24) = 0

Solve for x

x = 4 or x =-24

The width of the garden cannot be negative.

So, we have:

x = 4

Hence, the width of the garden is 4 feet

Read more about area at

brainly.com/question/24487155

#SPJ1

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In a dilation with a scale factor of 3/4,the image is __________ the preimage
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I would say smaller than because you would be dilating the image by a number less than 1, which is making the image smaller.
3 0
3 years ago
PLEASE HELPPPPP!!!!!!!!! (show work if you can)
Kryger [21]

Answer:

180x^4y^3z^2

Step-by-step explanation:

Start by finding the LCM of the coefficients of each polynomial:

LCM(12,18,30)=180

Next, to find the least common multiple of each of the following terms, we need to take the absolute minimum we can of each term (x, y, and z). The largest term of x is x^4 in the first polynomial, so we'll take exactly that for our x term in the LCM, absolutely nothing more. Similarly, the largest term of y in any of the three polynomials is y^3 (also in the first polynomial) and the largest z term in any of the three polynomials is z^2 in the second polynomial. Thus, the LCM of all our polynomials is:

180\cdot x^4\cdot y^3\cdot z^2=\boxed{180x^4y^3z^2}

3 0
3 years ago
Read 2 more answers
A cube-shaped box has a volume of 125 cubic inches. If the box is packed full of cubes with edge lengths of 1 inch, how many cub
harina [27]

I am not sure if I am right, but this is the best I can answer.


Useing reason, and logic, my guess would be if you take 125, and divided it by 4, you would get 31.25. that should be the answer... if i am wrong, i am truely sorry. I havent been in the subject in a while...


                                                           Hope this helps.


6 0
3 years ago
What is the inverse and restricted domain of the equation 8x^2-3
kari74 [83]

Answer:  \bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}

<u>Step-by-step explanation:</u>

y = 8x² - 3            (Restriction: none -  x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3            <em>swapped the x and y</em>

x + 3 = 8y²           <em>added 3 to both sides</em>

\dfrac{x+3}{8}=y^2           <em>divided both sides by 8</em>

\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}           <em>square rooted both sides</em>

\pm \sqrt{\dfrac{x+3}{8}}=y           <em>simplified</em>

\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y           rationalized the denominator

\pm \sqrt{\dfrac{2(x+3)}{16}}=y           <em>simplified</em>

\pm \dfrac{\sqrt{2(x+3)}}{4}=y           <em>simplified</em>

<u>Restriction:</u>

The radical <em>(inside the square root sign)</em> cannot be negative

→  2(x + 3) ≥ 0

      x + 3 ≥ 0         <em>divided both sides by 2</em>

      x       ≥ -3         <em>subtracted 3 from both sides</em>



4 0
3 years ago
Ralph sold brownies for $0.18 a piece in order to earn money to buy baseball cards. If the cards cost ​$0.90 per​ pack, and if R
german
Subtract the 0.18 by 0.90 maybe idk
3 0
3 years ago
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