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lubasha [3.4K]
2 years ago
9

What is the x-coordinate of the vertex of the parabola whose equation is y = 3x² + 9x?

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
5 0

Answer: x=-1,5.

Step-by-step explanation:

y=3x^2+9x\\\boxed {x=-\frac{b}{2a} }\\a=3,\ \ \ \ \ b=9.\\x=-\frac{9}{2*3}=-\frac{3}{2}=-1,5.

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The area of a soccer field at 7700 yd.². The width of the field is 70 yards. What is the perimeter of the field?
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3 years ago
What is the quotient
mario62 [17]

Answer:

The quotient is 3x - 11 + 60/(x + 5) ⇒ 2nd answer

Step-by-step explanation:

* We will use the long division to solve the problem

- The dividend is 3x² + 4x + 5

- The divisor is x + 5

- The quotient is the answer of the division

- If the divisor not a factor of a dividend, the quotient has

  a remainder

* Lets solve the problem

- At first divide the first term in the dividend by the first term in

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- Multiply the divisor by 3x

∴ 3x (x + 5) = 3x² + 15x

-Subtract this expression from the dividend

∴ 3x² + 4x + 5 - (3x² + 15x) = 3x² + 4x + 5 - 3x² - 15x = -11x + 5

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- Multiply the divisor by -11

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∴ -11x + 5 - (-11x - 55) = -11x + 5 + 11x + 55 = 60

∴ The quotient is 3x - 11 with remainder = 60

* The quotient is 3x - 11 + 60/(x + 5)

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