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adoni [48]
2 years ago
11

Which 2 number have the mean of 10 and range of 4

Mathematics
1 answer:
BigorU [14]2 years ago
5 0

Answer:

12 and 8

Step-by-step explanation:

→ Set up two equations

x - y = 4

\frac{x+y}{2} =10 \\ \\x + y = 20

→ Add the 2 equations together

2x = 24

→ Solve for x

x = 12

→ Substitute into original equation

12 - y = 4

→ Solve

y = 8

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Find the area of a circle having a radius of 9 cm
iVinArrow [24]

Answer:

81 pi cm^2

or approximately 254.34 cm^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

A = pi (9)^2

A = 81 pi

Using 3.14 as an approximation for pi

A = 81 (3.14)

A =254.34 cm^2

7 0
3 years ago
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What is the value of y in the equation 2(2y − 12) = 0? <br><br> 4<br><br> 6<br><br> 7<br><br> 8
Elena-2011 [213]
First you distribute making it 4y-24=0
second you isolate the variable making it 4y=24
finally you divide by four giving you the answer of y=6
4 0
3 years ago
What is the answer to this
Maurinko [17]

{x}^{2}  - 9x - 36 = 0 \\ (x - 12)(x + 3) = 0 \\ x - 12 = 0 \\ x = 12 \\ x  + 3 = 0 \\ x =  - 3
5 0
3 years ago
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3-1/8a=1/4<br><br> Pleasseeee help
Vika [28.1K]
3 - 1/8a = 1/4

The goal is to isolate "a" and its coefficient to make the simplification process easier.

Start by subtracting 3 from both sides:

3 - 3 - 1/8a = 1/4 -3

-1/8a = 1/4 - 3

Next, multiply 3 by 4/4 to convert it into a fraction:

-1/8a = 1/4 - [3 • (4/4)]

-1/8a = 1/4 - 12/4

-1/8a = - 11/4

Multiply both sides by -8:

(-8) -1/8a = - 11/4 (-8)

a = 88/4 = 22

Therefore, a = 22.
7 0
3 years ago
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Lifetime of $1 Bills The average lifetime of circulated $1 bills is 18 months. A researcher believes that the average lifetime i
OLEGan [10]
<h2>Answer with explanation:</h2>

Let \mu be the population mean lifetime of circulated $1 bills.

By considering the given information , we have :-

H_0:\mu=18\\\\H_a:\mu\neq18

Since the alternative hypotheses is two tailed so the test is a two tailed test.

We assume that the lifetime of circulated $1 bills is normally distributed.

Given : Sample size :  n=50 , which is greater than 30 .

It means the sample is large so we use z-test.

Sample mean : \overline{x}=18.8

Standard deviation : \sigma=2.8

Test statistic for population mean :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

\Rightarrow\ z=\dfrac{18.8-18}{\dfrac{2.8}{\sqrt{50}}}\approx2.02

The p-value= 2P(z>2.02)=0.0433834

Since the p-value (0.0433834) is greater than the significance level (0.02) , so we do not reject the null hypothesis.

Hence, we conclude that we do not have enough evidence to support the alternative hypothesis that the average lifetime of a circulated $1 bill differs from 18 months.

6 0
3 years ago
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