Improper fractions and mixed numbers are always greater than or equal to 1, while proper fractions are less than 1 and greater than 0. Improper fractions have a numerator that's bigger than it's denominator, while proper fractions have a numerator that's smaller than it's denominator.
The answer is (A) c = 0 or c = 4.
Answer:
238.095238%
Step-by-step explanation:
This involves basic arithmetic calculations and simultaneous equations.
Adamu has 25 Cards
Let the following letters represent the number of cards each has;
A: ADAMU
F: FUNKE
S: SHEHU
K: KWAME
T: TANKO
- If adamu gives funke 5 cards, he will have as many as tanko. Thus;
A - 5 = T --- eq 1
- If funke gives adamu 4 cards, he will have as many as kwame. Thus;
A + 4 = K --- eq 2
- Funke and adamu have a total of 13 more cards than the total that kwame and tanko have. Thus;
A + F = K + T + 13 --- eq 3
- Adamu has 2 cards more than what Shehu has. Thus;
A - 2 = S --- eq 4
From online research, the Total Number of cards is 134 and not 133. Thus;
A + F + K + S + T = 134 --- eq 5
Let's put A - 5 = T and A + 4 = K in eq 3 to get;
A + F = (A + 4) + (A - 5) + 13
A + F = 2A + 12
F = 2A - A + 12
F = A + 12
Let's put A - 2 = S ; F = A + 12 ; A - 5 = T and A + 4 = K into eq 5 to get;
A + A + 12 + A + 4 + A - 2 + A - 5 = 134
Simplifying gives;
5A + 9 = 134
5A = 134 - 9
5A = 125
A = 125/5
A = 25
Adamu has 25 Cards
