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anyanavicka [17]
2 years ago
12

Write an equation in slope-intercept form of the line containing the points (3,-1) and (6, 7).

Mathematics
1 answer:
umka2103 [35]2 years ago
7 0

The equation in slope-intercept form of the line containing the points (3,-1) and (6, 7) is; y = ⁸/₃x - 7

<h3>What is the equation in Slope Intercept form?</h3>

We are given the coordinates of two points as;

(3,-1) and (6, 7).

Now, the formula for the equation of the line containing the two points in slope intercept form is;

(y - y1)/(x - x1) = (y2 - y1)/(x2 - x1)

Thus, we have;

(y + 1)/(x - 3) = (7 + 1)/(6 - 3)

(y + 1)/(x - 3) = = 8/3

y + 1 = (8/3)(x - 3)

y + 1 = ⁸/₃x - 8

y = ⁸/₃x - 7

Read more about Slope intercept form at; brainly.com/question/1884491

#SPJ1

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                          All mainly from wiki and other online websites

8 0
3 years ago
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[Help asap, will mark brainliest] In the figure, line a is parallel to line b.
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Answer:

m <5 = 65°

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Step-by-step explanation:

m<2= m<5 = 65° (vertically opposite angles are equal)

m<5 + m<4 = 180 (co-int angles, parallel lines)

65+ m<4 =180

m<4 = 115°

Therefore

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Step-by-step explanation:

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