Answer:
g-1(x)=SQRT{(x-4)/2} + 4
Step-by-step explanation:
I assume that the 2 is the exponent so ^ represents exponent
We know your function is g(x)=2(x-3)^2+4
For inverse functions we swap x and y values, note g(x) is like the y value
Isolate for y
y=2(x-3)^2+4
x=2(y-3)^2+4
(x-4)/2 = (y-3)^2
SQRT{(x-4)/2} + 4 = y
Therefore g-1(x)=SQRT{(x-4)/2} + 4
Answer:
(c) x = 2 and x = -8
Step-by-step explanation:
The rules of logarithms let you rewrite this as a quadratic equation. That equation will have two (2) potential solutions. We know from the domain of the log function that any negative value of x will be an extraneous solution.
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The rules of logarithms that apply are ...

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<h3>take antilogs</h3>
We can rewrite the equation so that only one logarithm is involved. Then we can take antilogs.

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<h3>solve the quadratic</h3>
Adding (6/2)² = 9 to both sides will "complete the square."
16 +9 = x² +6x +9 . . . . . . . add 9
25 = (x +3)²
±√25 = x +3 = ±5 . . . . . take the square root(s)
x = -3 ±5 = {-8, +2}
The two potential solutions are x = 2 and x = -8.
Answer:
87.5%
Step-by-step explanation:
28/32=0.875
0.875*100= 87.5
87.5% of 32 = 28
Answer:
20 per hour
Step-by-step explanation:
divide 60 by 3=20