Answer:

Step-by-step explanation:
<u>Use the Pythagorean Theorem</u>
The equation for the Pythagorean Theorem is 
* a and b are the lengths of the legs, and c is the hypotenuse.*
(To know which side is the hypotenuse look at longest side which is across the right angle).
a= x, b=8, c=9

Let's Plug in the side lengths:

Evaluate 8^2 and 9^2:

Subtract 64 from both sides:


Take the square root of both sides:

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The answer should be 5.5 because you have to divide it. The fraction would be 5 over 10
Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
Answer:
0.064
Step-by-step explanation:
25000(1-0.8)^8
= 25000(0.2)^8
= 0.064
Factor the equation to give



By the zero product property, either x^2=0 or (3x^2+12-6x)=0 or both.
If x^2=0, then x=0
if (3x^2+12-6x)=0, we use the quadratic formula to solve for x
where x=1 ± √ (3) i
Answer: the roots of <span>3x^4+12x^2=6x^3 are {0 (multiplicity 2), 1+√3 i, 1-√3 i}</span>