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Free_Kalibri [48]
3 years ago
8

What is (5 hundreds 5 tens) x 10 in unit and standard form

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0
  • In unit form: 5 ones thousands 5 hundreds
  • In standard form: 5,500
<h3>Further explanation:</h3>

Problem: (5 hundreds 5 tens) x 10

Question: what is the result in unit and standard form

This is a problem with place value. In standard form, 5 hundreds 5 tens are 550.

Let's do the multiplication first.

Hence,

  • \boxed{ \ = (5 \ hundreds \ 5 \ tens) \times 10} \ }
  • \boxed{ \ = 550 \times 10} \ }
  • \boxed{\boxed{ \ = 5,500} \ }}

Now consider the result. Let's write the result in unit form and standard form.

  • In unit form: 5 ones thousands 5 hundreds
  • In standard form: 5,500

Remember these

  • A standard form ⇒ is written in number form
  • Unit form ⇒ writing a number using place value units

Another example

What is (5 hundreds 5 ones) x 10 in the unit and standard form?

In standard form, 5 hundreds 5 ones is 505.

Hence,

  • \boxed{ \ = (5 \ hundreds \ 5 \ ones) \times 10} \ }
  • \boxed{ \ = 505 \times 10} \ }
  • \boxed{\boxed{ \ = 5,050} \ }}

Let's write the result in unit form and standard form.

  • In unit form: 5 ones thousands 5 tens
  • In standard form: 5,050
<h3>Learn more</h3>
  1. What 3 digits are in the units period of 4,083,817 brainly.com/question/558692
  2. 9 ten thousand divided by 10 in unit form brainly.com/question/4786449
  3. Let's write 770, 070 in expanded form brainly.com/question/4725342

Keywords: what is, (5 hundreds 5 tens) x 10, 550, in unit form and standard form, millions, thousands, hundreds, tens, ones, place value, number form, 5,500

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lapo4ka [179]

Answer:

a) 40 feet

b) 54 ft/min

c) 4 mins

Step-by-step explanation:

Solution:-

- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.

- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:

                           h ( t ) = −16t² + 54t + 40

Which gives the height of the baton from ground at time t mins.

- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.

- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:

                         h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40

                         h ( 0 ) = hi = 0 + 0 + 40 = 40 feet

Answer: The height of the platform hi is 40 feet.

- The speed ( v ) during the parabolic path of the baton also varies with time t.

- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.

                        v ( t ) = dh / dt

                        v ( t )= d ( −16t² + 54t + 40 ) / dt

                        v ( t )= -2*(16)*t + 54

                        v ( t )= -32t + 54

- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.

Hence,

                        v ( 0 ) = vi = -32*( 0 ) + 54

                        v ( 0 ) = vi = 54 ft / min

Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min

- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.

- The height of the ball at ground is zero. Hence,

                     h ( t ) = 0

                     0 = −16t² + 54t + 40

                     0 = -8t^2 + 27t + 20

- Use the quadratic formula to solve the quadratic equation:

                     

                    t = \frac{27+/-\sqrt{27^2 - 4*8*(-20)} }{2*8}\\\\t = \frac{27+/-\sqrt{1369} }{16}\\\\t = \frac{27+/-37 }{16}\\\\t =  \frac{27 + 37}{16} \\\\t = 4

Answer: The time taken for the baton to hit the ground is t = 4 mins

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Last Year, a state university received 3,560 applications from boys. Of those applications, 35 Percent were from boys who lived
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Answer:

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