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Free_Kalibri [48]
4 years ago
8

What is (5 hundreds 5 tens) x 10 in unit and standard form

Mathematics
1 answer:
Ilia_Sergeevich [38]4 years ago
8 0
  • In unit form: 5 ones thousands 5 hundreds
  • In standard form: 5,500
<h3>Further explanation:</h3>

Problem: (5 hundreds 5 tens) x 10

Question: what is the result in unit and standard form

This is a problem with place value. In standard form, 5 hundreds 5 tens are 550.

Let's do the multiplication first.

Hence,

  • \boxed{ \ = (5 \ hundreds \ 5 \ tens) \times 10} \ }
  • \boxed{ \ = 550 \times 10} \ }
  • \boxed{\boxed{ \ = 5,500} \ }}

Now consider the result. Let's write the result in unit form and standard form.

  • In unit form: 5 ones thousands 5 hundreds
  • In standard form: 5,500

Remember these

  • A standard form ⇒ is written in number form
  • Unit form ⇒ writing a number using place value units

Another example

What is (5 hundreds 5 ones) x 10 in the unit and standard form?

In standard form, 5 hundreds 5 ones is 505.

Hence,

  • \boxed{ \ = (5 \ hundreds \ 5 \ ones) \times 10} \ }
  • \boxed{ \ = 505 \times 10} \ }
  • \boxed{\boxed{ \ = 5,050} \ }}

Let's write the result in unit form and standard form.

  • In unit form: 5 ones thousands 5 tens
  • In standard form: 5,050
<h3>Learn more</h3>
  1. What 3 digits are in the units period of 4,083,817 brainly.com/question/558692
  2. 9 ten thousand divided by 10 in unit form brainly.com/question/4786449
  3. Let's write 770, 070 in expanded form brainly.com/question/4725342

Keywords: what is, (5 hundreds 5 tens) x 10, 550, in unit form and standard form, millions, thousands, hundreds, tens, ones, place value, number form, 5,500

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Read 2 more answers
The length of a photograph is 3cm less than twice the width. The area is 54cm^2. Find the dimensions of the photograph.
REY [17]
W= width
l= length= 2w-3

Area= length * width
A= lw
substitute l=2w-3 for l
54= (2w-3)(w)
54= 2w^2 - 3w
subtract 54 from both sides
0= 2w^2 - 3w - 54
factor the polynomial
0= (2w + 9)(w - 6)

Set each set of parentheses equal
to 0 and solve for width.

0=2w+9
-9=2w
-4.5= w NEGATIVE VALUE

0=w-6
6 cm=w

-4.5 is not the answer because it has a negative value. You cannot have a negative side of a photograph. So substitute 6 in to find length.

length= 2w-3
l= 2(6)-3
l= 12-3
l= 9 cm

CHECK:
w= 6cm
l= 9cm
Area= length * width
54= 6*9
54= 54

ANSWER: width= 6cm; length= 9cm

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