Question

Find the remainder when f(X)=2x^3+2x^2-3x-3 is divided by X-2

Answer 1

The remainder when f(x) = 2x³ + 2x² - 3x - 3 is divided by x - 2 is 15.

We know that the remainder theorem states that if a polynomial p(x) is divided by a linear polynomial q(x) whose zero is x = a, then the remainder is given by r = p(a).

Here p(x) = f(x) = 2x³ + 2x² - 3x - 3 and q(x) = x - 2. First, we have to find the zero of q(x).

Now, q(x) = 0

i.e. x - 2 = 0

i.e. x = 2.

So, the zero of q(x) is 2, i.e. a = 2.

Then by the remainder theorem,

r = p(a) = f(2) = 2(2)³ + 2(2)² - 3(2) - 3 = 2 × 8 + 2 × 4 - 6 - 3 = 16 + 8 - 9 = 16 - 1 = 15

We can conclude that the remainder when f(x) = 2x³ + 2x² - 3x - 3 is divided by x - 2 is 15.

Know more about the remainder theorem here -

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