Answer:
perimeter = 20 m
Step-by-step explanation:
given the area of the square = 25 m² and
area of a square = s² ( where s is the side length ), then
s² = 25 ( take the square root of both sides )
s = 
= 5 ← length of side
perimeter = 4s = 4 × 5 = 20 m
Larger number is 32 because if u take 48 minus 16 u get your anwser
Hai !
6x+7+x^2+2x^2-3
6x+7+x^2+2x^2+-3
combine like terms
6x+7+x^2+2x^2+-3
(x^2+2x^2)+(6x)+(7+-3)
=3x^2+6x+4
Cheers :3
We need a system of equations here, one equation based on the NUMBER of tickets sold and another based on the MONEY earned by the sales. We have 2 different types of tickets: full price (f) and discount (d). The total number of tickets sold is 428; therefore, the first equation is f + d = 428. That accounts for the number of tickets sold. Each full price is 10.25 which can be represented as 10.25f, and each discount ticket costs 8 which can be represented as 8d. The money earned by selling these tickets at those prices was 3946. That means that the second equation is 10.25f + 8d = 3946. We will solve the first bolded equation for f to get f = 428 - d. Sub that value in for f in the second bolded equation: 10.25(428-d) + 8d = 3946. Distribute to get 4387 - 10.25d + 8d = 3946. Combine like terms to get -2.25d = -441. Solving for d we get 196. That means that there were 196 discounted tickets sold. Put that in for d in the first bolded equation to find the number of full price tickets. f + 196 = 428, and f = 232. There were 232 full price tickets sold. There you go!
<h2>
P(E) = 
or, 0.6092</h2>
Step-by-step explanation:
Given,
There are 348 identical plastic chips numbered 1 through 348 in a box.
To find, the probability of reaching into the box and randomly drawing a chip number which is smaller than 213 = ?
Total number of possible outcomes = 348
Let E be the event of getting randomly drawing a chip number that is smaller than 213.
Favourable outcomes are:
1, 2, 3, .............., 212
Number of favourable outcomes = 212
∴ Probability =
P(E) =
= or, 0.6092
Thus, P(E) = or, 0.6092
