Ask question

Ask question

All categories

2 years ago

10

A bag contains 39 colored marbles. There are 6 blue marbles, 14 red marbles, 8 yellow marbles, and 11 clear marbles. What is the

ratio of blue marbles to red marbles?

1 answer:

balu736 [363]2 years ago

3 0

Answer:

$6:14=3:7$

Step-by-step explanation:

There are 6 blue marbles and 14 red marbles, so the ratio of blue marbles to red marbles $=6:14=3:7$

You might be interested in

Subtract fractions with different denominators

Tems11 [23]

Answer:

$\frac{10}{15}-\frac{2}{5}=\frac{4}{15}$

Step-by-step explanation:

We know that

A fraction consists of two integers—one on the top, and one on the bottom.
The top one is numerator, the bottom one is denominator, and
These two numbers are separated by a line.

Let us consider two different fractions with different denominators

$\frac{10}{15}$

$\frac{2}{5}$

Lets subtract the two fractions

$\frac{10}{15}-\frac{2}{5}\:\:\:\:$

$\mathrm{Cancel\:}\frac{10}{15}:\quad \frac{2}{3}$

$=\frac{2}{3}-\frac{2}{5}$

$\mathrm{Least\:Common\:Multiplier\:of\:}3,\:5:\quad 15$

$\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}$

$\mathrm{For}\:\frac{2}{3}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:5$

$\frac{2}{3}=\frac{2\cdot \:5}{3\cdot \:5}=\frac{10}{15}$

$\mathrm{For}\:\frac{2}{5}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:3$

$\frac{2}{5}=\frac{2\cdot \:3}{5\cdot \:3}=\frac{6}{15}$

so

$=\frac{10}{15}-\frac{6}{15}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{10-6}{15}$

$\mathrm{Subtract\:the\:numbers:}\:10-6=4$

$=\frac{4}{15}$

Therefore,

$\frac{10}{15}-\frac{2}{5}=\frac{4}{15}$

5 0

3 years ago

Look at the question, please orginize it in a good manner. NO LINKS!

tia_tia [17]

Answer:

for the first one its right 2 down 5

for the second one its right 5 down 2

for the third one its left 2 up 5

i hope this helps pls tell me if im wrong

3 0

3 years ago

Read 2 more answers

What is x, the angle at which the diagonal beam meets the 10-foot beam at the top of the frame? 16.7° 17.5° 72.5° 73.3°

umka21 [38]

The complete question is

"A theater production group is making frames to support wall-like props. Three-foot beams form right triangles with 10-foot beams to allow them to stand, as shown in the image.

What is x, the angle at which the diagonal beam meets the 10-foot beam at the top of the frame?

16.7°, 17.5°, 72.5°,73.3°"

The value of angle x would be 16.7 degrees.

<h3>What is the right triangle?</h3>

A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse.

The angle of a right angle is always 90 degrees.

In order to find the value of x, a tan would be used.

This is because we have given the opposite and adjacent sides as 10 ft and 3 ft.

Tan Ф = opposite / adjacent

Tan Ф = (3/10)

= 16.7 degrees

The value of angle x would be 16.7 degrees.

Learn more about a right angle;

brainly.com/question/7116550

#SPJ1

6 0

2 years ago

The following data gives the scores of 13 students in a Biostatistics exam. 75 80 28 70 95 82 75 64 61 90 81 65 91 a) Find the f

Radda [10]

Answer:The following data gives the scores of 13 students in a Biostatistics exam. 75 80 28 70 95 82 75 64 61 90 81 65 91 a) Find the following statistical measures 1. Mean 2. Median 3. Mode 4. Range 5. 34th percentile 6. Interquartile Range 7. Variance 8. Standard deviation PRINCIPLES OF STATISTICS Assignment (1) Due Date: 15/7/2020 9. Coefficient of variation. b) (Without Calculations) If the instructor decide to add up 5 marks for every student, what are the values of the statistical measures mentioned in part (a). c) Construct the Boxplot of students' scores, and identify any possible outliers.

6 0

3 years ago

The surface areas of two similar figures are 25 in2 and 36 in2. If the volume of the smaller figure is 250 in3, what is the volu

Slav-nsk [51]

Since the figures are similar, we can establish a rule of three as follows.
We know that the area of the smaller figure is $25in^{2}$ , and its volume is $250in^{3}$ . We also know that the area of the larger figure is $36in^{2}$ ; since we don't now its volume, lets represent it with $X$ :
$\frac{25in^{2}----\ \textgreater \ 250in^{3}}{36in^{2}----\ \textgreater \ Xin^{3}}$
$\frac{25}{36} = \frac{250}{X}$
$X= \frac{(250)(36)}{25}$
$X=360$

We can conclude that the volume of the larger figure is $360in^{3}$ ; therefore, the correct answer is a.

6 0

3 years ago

Read 2 more answers