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Zina [86]
2 years ago
6

Solve for k in g=k-a.​

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
5 0

Answer:

k = g + a

Step-by-step explanation:

g = k - a ( add a to both sides )

g + a = k , that is

k = g + a

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The average number of employees that call in sick for the day over the course of a year is 25. The number of employees that call
morpeh [17]

Answer:

sample mean (x with the bar on top) =24

Step-by-step explanation:

Take the mean of all the number of employees but divide by the number of days size: (25+10+16...)/12=25

population mean (mu) =11.52

The same goes for the other one but divide by the population which is 25

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3 years ago
Solve (x+6)square =40
Kryger [21]
Approximately 0.3246 (rounded to the nearest ten thousandth). Find the square root of 40, then subtract 6.
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Subtract 5x^2-8x-1 from <br> -(5x^2 -x - 8).
Jobisdone [24]

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-10x² - 7x + 7

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Subtract:

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Remember: subtracting a negative number is adding that number

-Chetan K

3 0
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At a school with 100? students, 33 were taking? Arabic, 32 ?Bulgarian, and 40 Chinese. 9 students take only? Arabic, 12 take onl
Stels [109]

Answer: The answer is 4 and 32.

Step-by-step explanation: Let "A", "B" and "C" represents the set of students who were taking Arabic, Bulgarian and Chinese respectively.

The, according to the given information, we have

n(A)=33,~~n(B)=32,~~n(C)=40,~~n(A\cap B)=14.

Let 'p' represents the number of students who take all the three languages, then

n(A\cap B\cap C)=p.

Also,

n(A)-n(A\cap B)-n(A\cap C)+n(A\cap B\cap C)=9\\\\\Rightarrow n(A\cap B)+n(A\cap C)=24+p~~~~~~~~~~~~~~(a),\\\\n(A\cap B)+n(B\cap C)=20+p~~~~~~~~~~~~~~(b),\\\\n(B\cap C)+n(A\cap C)=20+p~~~~~~~~~~~~~~~(c).

From here, we get after subtracting equation(c) from (b) that

n(A\cap B)=n(A\cap C)=14.

Therefore,

p=14+14-24=4, and from equation (a), we find

n(B\cap C)=24-14=10.

Thus,

n(A\cap B\cap C)=4 and

n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)\\\\\Rightarrow n(A\cap B\cap C)=33+32+40-9-12-20+4\\\\\Rightarrow n(A\cap B\cap C)=68.

Thus, the number of students who take all the three languages is 4 and the number of students who take none of the languages is 100-68 = 32.

5 0
3 years ago
[-4 + n - 2n x 2n] + [ 2 - 5n - 6n x 6n]​
Kamila [148]

Answer:

- 2 - 4n - 8n²  

Step-by-step explanation:

thats ur anser

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3 years ago
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