All categories

2 years ago

Solve for k in g=k-a.

Mathematics

1 answer:

Varvara68 [4.7K]2 years ago

5 0

Answer:

k = g + a

Step-by-step explanation:

g = k - a ( add a to both sides )

g + a = k , that is

k = g + a

You might be interested in

The average number of employees that call in sick for the day over the course of a year is 25. The number of employees that call

morpeh [17]

Answer:

sample mean (x with the bar on top) =24

Step-by-step explanation:

Take the mean of all the number of employees but divide by the number of days size: (25+10+16...)/12=25

population mean (mu) =11.52

The same goes for the other one but divide by the population which is 25

4 0

3 years ago

Solve (x+6)square =40

Kryger [21]

Approximately 0.3246 (rounded to the nearest ten thousandth). Find the square root of 40, then subtract 6.

4 0

3 years ago

Read 2 more answers

Subtract 5x^2-8x-1 from <br> -(5x^2 -x - 8).

Jobisdone [24]

Answer:

-10x² - 7x + 7

Step-by-step explanation:

Subtract:

-5x² - 8x - 1 - (5x² - x - 8)
-5x² - 5x² - 8x + x - 1 + 8
-10x² - 7x + 7

Remember: subtracting a negative number is adding that number

-Chetan K

3 0

2 years ago

Read 2 more answers

At a school with 100? students, 33 were taking? Arabic, 32 ?Bulgarian, and 40 Chinese. 9 students take only? Arabic, 12 take onl

Stels [109]

Answer: The answer is 4 and 32.

Step-by-step explanation: Let "A", "B" and "C" represents the set of students who were taking Arabic, Bulgarian and Chinese respectively.

The, according to the given information, we have

$n(A)=33,~~n(B)=32,~~n(C)=40,~~n(A\cap B)=14.$

Let 'p' represents the number of students who take all the three languages, then

$n(A\cap B\cap C)=p.$

Also,

$n(A)-n(A\cap B)-n(A\cap C)+n(A\cap B\cap C)=9\\\\\Rightarrow n(A\cap B)+n(A\cap C)=24+p~~~~~~~~~~~~~~(a),\\\\n(A\cap B)+n(B\cap C)=20+p~~~~~~~~~~~~~~(b),\\\\n(B\cap C)+n(A\cap C)=20+p~~~~~~~~~~~~~~~(c).$

From here, we get after subtracting equation(c) from (b) that

$n(A\cap B)=n(A\cap C)=14.$

Therefore,

$p=14+14-24=4,$ and from equation (a), we find

$n(B\cap C)=24-14=10.$

Thus,

$n(A\cap B\cap C)=4$ and

$n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)\\\\\Rightarrow n(A\cap B\cap C)=33+32+40-9-12-20+4\\\\\Rightarrow n(A\cap B\cap C)=68.$

Thus, the number of students who take all the three languages is 4 and the number of students who take none of the languages is 100-68 = 32.

5 0

3 years ago

[-4 + n - 2n x 2n] + [ 2 - 5n - 6n x 6n]

Kamila [148]

Answer:

- 2 - 4n - 8n²

Step-by-step explanation:

thats ur anser

3 0

3 years ago

Solve for k in g=k-a.​

Solve for k in g=k-a.