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3 years ago

Seven people meet and shake hands with one another. how many handshakes occur ?

Mathematics

2 answers:

N76 [4]3 years ago

7 0

If seven people meet and shake hands with each other, then each person will shake each person's hand at least one time.

7*7=49.

There will be 49 handshakes.

Kryger [21]3 years ago

5 0

49 shakes in total. 7x7=49

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3 years ago

A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners

Vlada [557]

Answer:

The measures of the angles at its corners are $59.1\°,35.4\°,85.5\°$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

$185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)$

$2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}$

$cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))$ $cos(A)=0.513953$

$A=arccos(0.513953)=59.1\°$

step 2

Find the measure of angle B

Applying the law of cosines

$125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)$

$2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}$

$cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))$ $cos(B)=0.81489$

$B=arccos(0.81489)=35.4\°$

step 3

Find the measure of angle C

Applying the law of cosines

$215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)$

$2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}$

$cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))$ $cos(C)=0.0784$

$C=arccos(0.0784)=85.5\°$

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3 years ago

What is the surface area of the regular pyramid below? I’ll would be helpful if you guys list down the steps !

meriva

Answer:

The answer to your question is A = 648 u²

Step-by-step explanation:

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4 years ago

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ziro4ka [17]

Answer:

The second choices is the answer

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3 years ago

What is 7.3 = y + 2.8

zloy xaker [14]

Answer:

4.5

Step-by-step explanation:

7.3= y + 2.8

Subtract 2.8 from both sides

7.3 = y+ 2.8

-2.8 -2.8

--------------------

y = 4.5

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3 years ago

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